如何從Java字符串中刪除括號？

Question

我的Java應用程序將獲取以下形式的字符串：

How now [[brown cow ]]. The arsonist [[ had oddly shaped ]] feet. The [[human torch was denied]] a bank loan.

並且需要一個正則表達式/方法來去除[[ ]]每個實例（以及所有包含文本），從而將上述字符串轉換為：

How now. The arsonist  feet. The  a bank loan.

注意保持雙位（與arsonist和feet ，以及之間The和a ）？ 這也很重要。

不知道這里的正則表達式是否合適，或者是否有更有效的方法來剔除不需要的[[ ]]實例。

Answer 1

這是在javascript中。

var text = "How now [[brown cow ]]. The arsonist [[ had oddly shaped ]] feet. The [[human torch was denied]] a bank loan."
text.replace(/\[\[[^\]]+\]\]/g, "")

匹配括號的正則表達式將是

/\[\[[^\]]+\]\]/g

因此，Java等價於

text.replaceAll("\[\[[^\]]+\]\]", "");

並將其替換為空字符串

可以刪除雙括號和三括號的正則表達式

text.replaceAll("\[?\[\[[^\]]+\]\]\]?", "")

Answer 2

這對於replaceAll很簡單

str = str.replaceAll( "\\[\\[[^\\]]*\\]\\]", "" );

假定括號之間沒有] 。

Answer 3

嘗試使用以下代碼：

public class Test{
public static void main(String[] args) {
    String input = "How now [[brown cow ]]. The arsonist [[ had oddly shaped ]] feet. The [[human torch was denied]] a bank loan.";
    // Will replace all data within braces []
    String replaceAll = input.replaceAll("(\\[.+?\\])|(\\])", "");
    System.out.println(replaceAll);
}

}

希望這可以幫助。

Answer 4

tring s = "How now [[brown cow ]]. The arsonist [[ had oddly shaped ]] feet. The [[human torch was denied]] a bank loan.";

s=s.replaceAll("\\[.*?\\]","").replace("]","");

輸出：

How now . The arsonist  feet. The  a bank loan.