[英]HttpPost send GET to the server
我的問題已解決,服務器的所有者刪除了一些代碼,以檢查發送POST / GET方法的基礎是否正常,並且工作正常。
我仍然不知道問題出在哪里,但是肯定不是我的問題。
我正在嘗試將POST
方法發送到服務器,但事實證明服務器改為使用GET
方法。 我們在iPhone上運行了它,因此服務器是正確的。
這是我編寫的用於發送數據的代碼:
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://myurl.nl/casus");
httppost.setHeader("Authorization", "xxxxxxxxxxxxxxx");
try {
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
//casus
nameValuePairs.add(new BasicNameValuePair("casusid", casus.id+""));
String woorden = "[";
for(int i = 0; i < words.length; i++){
woorden += "\""+words[i]+"\"";
if(i != words.length-1){
woorden += ",";
}
}
woorden += "]";
nameValuePairs.add(new BasicNameValuePair("woorden", woorden));
//info
SharedPreferences sharedPref = getSharedPreferences("omapp", MODE_PRIVATE);
String age = sharedPref.getString("age", "");
String sex = sharedPref.getString("sex", "");
nameValuePairs.add(new BasicNameValuePair("leeftijdscategorie", age));
nameValuePairs.add(new BasicNameValuePair("geslacht", sex));
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse response = httpclient.execute(httppost);
String responseBody = EntityUtils.toString(response.getEntity());
Log.d("json", responseBody);
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
}catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
PHP代碼:
// Service token authorization.
require_once('../classlib/Auth.php');
$auth = new Auth;
if ( !$auth->valid() ) {
header('HTTP/1.1 401 Unauthorized');
exit;
}
// Setup casussen.
require_once('../classlib/PDOFactory.php');
require_once('../classlib/Casussen.php');
$casussen = new Casussen;
$casussen->setPDO(PDOFactory::create());
$rs = (object) array();
switch ( $_SERVER['REQUEST_METHOD'] ) {
case 'GET': {
mail('sdgsdgsdg@gmail.com', 'The get method was called', print_r($_SERVER,1));
$fromcasusid = !empty($_GET['fromcasusid']) ? (int) $_GET['fromcasusid'] : null;
$rs->casussen =$casussen->get($fromcasusid);
break;
}
case 'POST': {
mail('jsdgsdgsn@gmail.com', 'The post method was called', print_r($_SERVER,1));
$casusreactie = json_decode(file_get_contents("php://input"));
try {
$casussen->post($casusreactie);
} catch ( Exception $e ) {
$rs->error = (object) array(
'code' => $e->getCode(),
'message' => $e->getMessage(),
);
}
break;
}
default: {
header('HTTP/1.1 405 Method Not Allowed');
exit;
}
} // switch
header('Content-type: application/json; charset=utf-8');
exit(json_encode($rs));
一種鍛煉
從doGet內部調用doPost方法
public void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException{
doPOst(request, response)
}
我也有類似的問題。 我可以通過添加“ www”來修復它。 到網址。 但是我想知道這有什么不同,我已經成功使用jQuery ajax請求測試了服務器處理,而沒有使用“ www”。 。
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