整數形式的字符串列表['123 121'，'42 23'，'23 23']

Question

['136 145', '136 149', '137 145', '138 145', '139 145', '142 149', '142 153', '145 153']我想將上面的列表元素轉換為整數，我知道僅對[int(x) for x in mylist]使用[int(x) for x in mylist]行不通的。 所以我的問題是如何將我擁有的清單轉換為整數清單。

Answer 1

>>> L = ['136 145', '136 149', '137 145', '138 145', '139 145', '142 149', '142 153', '145 153']
>>> [int(y) for x in L for y in x.split()]
[136, 145, 136, 149, 137, 145, 138, 145, 139, 145, 142, 149, 142, 153, 145, 153]

Answer 2

首先分割文本， 然后轉換為int：

[map(int, elem.split()) for elem in originallist]

對於Python 3，其中map()返回一個生成器，而不是一個列表，您可以嵌套列表理解：

[[int(n) for n in elem.split()] for elem in originallist]

在Python 2下同樣可以正常工作。

快速演示：

>>> originallist = ['136 145', '136 149', '137 145', '138 145', '139 145', '142 149', '142 153', '145 153']
>>> [[int(n) for n in elem.split()] for elem in originallist]
[[136, 145], [136, 149], [137, 145], [138, 145], [139, 145], [142, 149], [142, 153], [145, 153]]

您可以通過將elem.split()循環移到外部列表理解末尾來刪除嵌套：

[int(n) for elem in originallist for n in elem.split()]

這使：

[136, 145, 136, 149, 137, 145, 138, 145, 139, 145, 142, 149, 142, 153, 145, 153]

Answer 3

由於我會竭盡全力避免嵌套列表的理解（我永遠不記得順序），所以我會做類似的事情：

from itertools import chain
x = ['136 145', '136 149', '137 145', '138 145', '139 145', '142 149', '142 153', '145 153']
gen = chain.from_iterable(elem.split() for elem in x)
integers = [int(elem) for elem in gen]

Answer 4

你可以這樣嘗試

>>> import re
>>> l=['136 145', '136 149', '137 145', '138 145', '139 145', '142 149', '142 153', '145 153']    
>>> map(int, re.findall(r'\d+',' '.join(l)))
[136, 145, 136, 149, 137, 145, 138, 145, 139, 145, 142, 149, 142, 153, 145, 153]

Answer 5

>>> L = ['136 145', '136 149', '137 145', '138 145', '139 145', '142 149', '142 153', '145 153']
>>> map(int, ' '.join(L).split())
[136, 145, 136, 149, 137, 145, 138, 145, 139, 145, 142, 149, 142, 153, 145, 153]