將String數組作為POST傳遞給PHP

Question

我試圖將一個字符串數組作為POST數據傳遞給PHP腳本但不確定該怎么做。

這是我到目前為止執行PHP腳本的代碼：

我試圖傳遞數組的地方：

nameValuePairs.add(new BasicNameValuePair("message",message));
String [] devices = {device1,device2,device3};
nameValuePairs.add(new BasicNameValuePair("devices", devices));// <-- Can't pass String[] to BasicNameValuePair
callPHPScript("notify_devices", nameValuePairs);

調用PHP腳本：

public String callPHPScript(String scriptName, List<NameValuePair> parameters) {
    HttpClient client = new DefaultHttpClient();
    HttpPost post = new HttpPost("http://localhost/" + scriptName);
    String line = "";
    StringBuilder stringBuilder = new StringBuilder();
    try {
        post.setEntity(new UrlEncodedFormEntity(parameters));

        HttpResponse response = client.execute(post);
        if (response.getStatusLine().getStatusCode() != 200)
        {
            System.out.println("DB: Error executing script !");
        }
        else {
            BufferedReader rd = new BufferedReader(new InputStreamReader(
                response.getEntity().getContent()));
            line = "";
            while ((line = rd.readLine()) != null) {
                stringBuilder.append(line);
            }
        }

    } catch (IOException e) {
        e.printStackTrace();
    }
    System.out.println("DB: Result: " + stringBuilder.toString());
    return stringBuilder.toString();
}

和PHP腳本有問題：

<?php
include('tools.php');
// Replace with real BROWSER API key from Google APIs
$apiKey = "123456";

// Replace with real client registration IDs 
$registrationIDs = array($_POST[devices]); <-- Where I want to pass array to script

// Message to be sent
$message = $_POST['message'];

// Set POST variables
$url = 'https://android.googleapis.com/gcm/send';

$fields = array(
                'registration_ids'  => $registrationIDs,
                'data'              => array( "message" => $message ),
                );

$headers = array( 
                    'Authorization: key=' . $apiKey,
                    'Content-Type: application/json'
                );

// Open connection
$ch = curl_init();

// Set the url, number of POST vars, POST data
curl_setopt( $ch, CURLOPT_URL, $url );

curl_setopt( $ch, CURLOPT_POST, true );
curl_setopt( $ch, CURLOPT_HTTPHEADER, $headers);
curl_setopt( $ch, CURLOPT_RETURNTRANSFER, true );

curl_setopt( $ch, CURLOPT_POSTFIELDS, json_encode( $fields ) );

// Execute post
$result = curl_exec($ch);

// Close connection
curl_close($ch);

print_as_json($result);
?>

有任何想法嗎？ 謝謝 ！

編輯

我正在嘗試以下但仍然沒有快樂：

public void notifyDevices(Message message) {

    List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
    List<String> deviceIDsList = new ArrayList<String>();
    String [] deviceIDArray;

    //Get devices to notify
    List<JSONDeviceProfile> deviceList = getDevicesToNotify();

    for(JSONDeviceProfile device : deviceList) {
        deviceIDsList.add(device.getDeviceId());
    }

    //Array of device IDs
    deviceIDArray = deviceIDsList.toArray(new String[deviceIDsList.size()]);
    for(String deviceID : deviceIDArray) {

        nameValuePairs.add(new BasicNameValuePair("devices[]", deviceID));

    }

    //Call script
    callPHPScript("GCM.php", nameValuePairs);
}

這就是我所有的“錯誤報告”......

        HttpResponse response = client.execute(post);
        if (response.getStatusLine().getStatusCode() != 200)
        {
            System.out.println("DB: Error executing script !");
        }

Answer 1

要在查詢字符串中將數組傳遞給php，您應該將[]添加到標識符並將每個項目添加為單獨的條目，因此這樣的事情應該起作用：

nameValuePairs.add(new BasicNameValuePair("devices[]", device1));
nameValuePairs.add(new BasicNameValuePair("devices[]", device2));
nameValuePairs.add(new BasicNameValuePair("devices[]", device3));

現在，PHP端的$_POST['devices']將包含一個數組。

Answer 2

我認為你應該對你的設備數組進行json編碼，這樣你就可以獲得一個字符串，你可以將它傳遞給BasicNameValuePair（...）。 在你的PHP代碼中，你只需要使用json_decode來獲取一個數組。

JSONArray devices = new JSONArray();
devices.put(device1);
devices.put(device2);
devices.put(device3);

String json = devices.toString();
nameValuePairs.add(new BasicNameValuePair("devices", devices));

在你的PHP代碼中：

$devices = $_POST['devices'];
$devices = json_decode($devices);

Answer 3

首先，在PHP中訪問$_POST數組時，您缺少單引號。 改變線

$registrationIDs = array($_POST[devices]);

至：

$registrationIDs = array($_POST['devices']);

您應該使用ini值display_errors ， log_errors ， error_reporting啟用錯誤日志記錄或PHP錯誤消息的輸出以進行調試，以了解此類錯誤。

---

但即使是array($_POST['devices'])也不會做出可能的預期。 array(...)是php中的數組初始化構造。 這意味着你只需將（$ _POST ['devices']）包裝到另一個數組中。

...想看var_dump($_POST);的輸出var_dump($_POST); 。 這會讓我有機會進一步幫助..