如何在向量中打印內容

Question

我是C ++的新手。 我想在“向量”中打印一些值。

vector<GLubyte> m_coneIndices;
m_coneIndices.resize(m_bodyIndexCount + m_diskIndexCount);
vector<GLubyte>::iterator index = m_coneIndices.begin();

// Body triangles
for (int i = 0; i < coneSlices * 2; i += 2) {
    *index++ = i;
    *index++ = (i + 1) % (2 * coneSlices);
    *index++ = (i + 3) % (2 * coneSlices);
}


// Disk triangles
for (int i = 1; i < coneSlices * 2 + 1; i += 2) {
    *index++ = diskCenterIndex;
    *index++ = i;
    *index++ = (i + 2) % (2 * coneSlices);
}

這就是將值存儲在“向量”中的方式。 我試過像

cout << "indices"<< "\n";

for (int i=0; i<(coneSlices * 2 ); i+=2) {

    cout << m_coneIndices[i] << ' ' << m_coneIndices[i+1] << ' ' << m_coneIndices[i+2] << ' ' << "\n";
}

然后打印出一些垃圾值。 讓我知道這段代碼有什么問題。

Answer 1

使用push_back添加到向量

vector<GLubyte> m_coneIndices;

// Body triangles
for (int i = 0; i < coneSlices * 3; i += 3) {
    m_coneIndices.push_back(i);
    m_coneIndices.push_back((i + 1) % (2 * coneSlices));
    m_coneIndices.push_back((i + 3) % (2 * coneSlices));
}

// Disk triangles
for (int i = 1; i < coneSlices * 2 + 1; i += 2) {
    m_coneIndices.push_back(diskCenterIndex);
    m_coneIndices.push_back(i);
    m_coneIndices.push_back((i + 2) % (2 * coneSlices));
}

打印：

cout << "indices"<< "\n";

for (size_t i = 0; i< m_coneIndices.size(); i+=3) {
    cout << m_coneIndices[i*3] << ' ' << m_coneIndices[i*3+1] << ' ' <<
            m_coneIndices[i*3+2] << ' ' << "\n";
}

Answer 2

我做得對。 我更改了代碼

for (int i=0; i<(coneSlices * 2 ); i+=2) {

     printf("%d ",(int)m_coneIndices[i]);
}

並且有效。