長期在Java中被視為數組中的int

Question

我已經將變量定義為long，當我嘗試將其用作數組中的一個變量時，它會繼續拋出一個錯誤，說我的值超出了int范圍。 嗯，不開玩笑，這很長，我把它定義為一個。

以下是我的代碼。 在第二課，LoanOfficer，你會發現第二個申請人比爾蓋茨，其年收入為3,710,000,000，這就是錯誤。

public class Applicant {
    private String name;
    private int creditScore;
    private long annualIncome;
    private int downPayment;
    private boolean status;

    public Applicant(String name, int creditScore, long annualIncome,
            int downPayment) {
        this.name = name;
        this.creditScore = creditScore;
        this.annualIncome = annualIncome;
        this.downPayment = downPayment;
        this.status = false;
    }

    public String getName() {
        return name;
    }

    public int getCreditScore() {
        return creditScore;
    }

    public long getAnnualIncome() {
        return annualIncome;
    }

    public int getDownPayment() {
        return downPayment;
    }

    public void setStatus(boolean status) {
        this.status = status;
    }

    public boolean isStatus() {
        return status;
    }
}

public class LoanOfficer {
    public static void main(String[] args) {
        Applicant[] applicants = {
                new Applicant("MC Hammer", 400, 25000, 5000),
                new Applicant("Bill Gates", 850, 3710000000, 500000),
                new Applicant("MC Hammer", 400, 25000, 5000),
                new Applicant("MC Hammer", 400, 25000, 5000), };
    }
}

Answer 1

對於被視為long的數字，您需要L后綴：

new Applicant("Bill Gates", 850, 3710000000L, 500000)

如果缺少L后綴，編譯器會將文字視為int 。

Answer 2

您需要通過附加L指定3710000000作為長文字：

new Applicant("Bill Gates", 850, 3710000000L, 500000),

來自JLS

如果整數文字后綴為ASCII字母L或l（ell），則整數文字的長度為long; 否則它是int類型

Answer 3

將3710000000更改為3710000000L。 問題是沒有L ，Java會把它當作int 。