為什么我的代碼對else語句不起作用？

Question

有人可以幫我做我的代碼嗎？ 我寫了一個小程序只是為了學習一些功能以及正在發生的事情。 讓我向您展示我的代碼。

print "Hello student need help multiplying by any mutiplicaton"
student = raw_input("If so then tell me which ones? => ").lower()
for i in range(0, 11):
    if student == str(0):
       i_num = 0 * i
       print "0 times %d equals %d" % (i,i_num)
    elif student == str(10):
       i_num = 1 * 1
       print "1 times %d equals %d" % (i,i_num)
else:
    print "Try this program when you can't figure it out your multiplications."

如果學生輸入的內容與if語句無關，則將打印else。 但是，如果學生輸入str（1），它將打印乘法，也將打印else，這就是我不想發生的代碼問題。 誰能幫我。 我只是想學習if和elif以及所有這些功能。

Answer 1

將else設置為在成功完成for循環時運行，請看縮進。 如果將其移動到循環中，則一切正常。 您的代碼確實包含一些語法錯誤。

程序的固定版本：

print "Hello student need help multiplying by any mutiplicaton"
student = raw_input("If so then tell me which ones? => ") # no need for lower()
for i in range(0, 11):
    if student == '0':
        i_num = 0 * i
        print "0 times %d equals %d" % (i,i_num)
    elif student == '1':
        i_num = 1 * 1
        print "1 times %d equals %d" % (i,i_num)
    else:
        print "Try this program when you can't figure it out your multiplications."

但是乘法很容易，所以為什么不這樣做：

print "Hello student need help multiplying by any mutiplicaton"
num = int(raw_input("If so then tell me which ones? => "))
for i in range(0, 11):
    print "%d times %d equals %d" % (num, i, i * num)

Answer 2

您在這里缺少）：

elif student == str(10):

Answer 3

def isAnInt(s):
   try: 
      int(s)
      return True
   except ValueError:
    print "You must enter a number"


print "Hello student need help multiplying by any mutiplicaton"
student = raw_input("If so then tell me which ones? => ")
if(isAnInt(student)):
  number_to_calc = int(student)
  for i in range(0,11):
    i_num = number_to_calc * i
    print "%d times %d equals %d" % (number_to_calc, i, i_num)