Android-使用RESTful API將數據寫入數據庫

Question

我是Android初學者，正在開發一個程序，該程序從本機設備電話簿中讀取聯系人並將其寫入數據庫（）。

我可以從手機中獲取和讀取聯系人，但是我被困在“將聯系人寫入數據庫”中。 這是我必須遵循的准則：

write function: 
write: 
[{'activity':'writeData', 
  'firstname':'Janis', 
  'lastname':'Berzins', 
  'telnr': '12312312'}]

request should be sent as: [{'activity':'readData'}]

example for read: [{"firstname":"Vards","lastname":"Uzvards","telnr":"12345678"},{"firstname":"Viesturs","lastname":"Lapsa","telnr":"11223344"}]

我花了四天時間研究了無數的教程，文檔等，這是我認為應該用於發送到數據庫的部分：

public static HttpResponse doPost(String url, JSONObject c) throws ClientProtocolException, IOException 
{
    HttpParams httpParams = new BasicHttpParams();
    HttpClient httpclient = new DefaultHttpClient(httpParams);
    HttpPost request = new HttpPost(url);
    StringEntity s = new StringEntity(c.toString());
    s.setContentEncoding("UTF-8");
    s.setContentType(new BasicHeader(HTTP.CONTENT_TYPE,"application/json"));

    request.setEntity(s);
    request.addHeader("accept", "application/json");

    return httpclient.execute(request);
}

為了創建一個簡單的測試Json，我使用了此類：

    public class RestPost extends AsyncTask<String, Void, String>
{
    @Override
    protected String doInBackground(String... params) {
        JSONObject json = new JSONObject();

        try
        {
            json.put("activity", "writeData");
            json.put("firstname", "Janis");
            json.put("lastname", "Berzins");
            json.put("telnr", "123123123");

            RestMethods.doPost(Main.server, json);
        }

        catch (JSONException e)
        {
            // TODO Auto-generated catch block
            e.printStackTrace();
            Log.i("Error: ", e.toString());
        }
        catch (ClientProtocolException e)
        {
            // TODO Auto-generated catch block
            e.printStackTrace();
            Log.i("Error: ", e.toString());
        }
        catch (IOException e)
        {
            // TODO Auto-generated catch block
            e.printStackTrace();
            Log.i("Error: ", e.toString());
        }
        Log.i("DONE ", " I GUES");
        return null;
    }
}

但是，在我的Android應用執行完此功能后-數據庫（）中沒有任何更改。

所以，請，有人可以幫我弄清楚我在做什么錯嗎？

謝謝！

Answer 1

您需要一個json數組（請參閱規范中json周圍的“ [“和”]“字符。

    JSONArray jsonArray = new JSONArray();
    // your code to create the JSONObject
    // ...
    jsonArray.put(json);

    // use this within your RestMethods call
    RestMethods.doPost(Main.server, jsonArray);

您可能可以一次將多個對象發送到服務器-即使“規范”沒有提及，使用數組也可以提示您。

Answer 2

好的，我可以將其發送到數據庫了！ :)現在，我正在使用Get方法..這就是我得到的-現在看來似乎無法正常工作，可能是由於數據庫中的數據作為JSONArray發送的事實？

public static JSONObject doGet(String url)
{
    JSONObject json = null;

    HttpClient httpclient = new DefaultHttpClient();
    HttpGet httpget = new HttpGet(url); 

    httpget.addHeader("accept", "application/json");
    HttpResponse response;

    try {
        response = httpclient.execute(httpget);
        HttpEntity entity = response.getEntity();    

        if (entity != null) 
        {
            InputStream instream = entity.getContent();
            String result= convertStreamToString(instream);
            json=new JSONObject(result);     
            instream.close();
        }   
    } 

    catch (ClientProtocolException e) 
    {
        // TODO Auto-generated catch block
        e.printStackTrace();
        Log.i("Error: ", e.toString());
    } 
    catch (IOException e) 
    {
        // TODO Auto-generated catch block
        e.printStackTrace();
        Log.i("Error: ", e.toString());
    } 

    catch (JSONException e) 
    {
        // TODO Auto-generated catch block
        e.printStackTrace();
        Log.i("Error: ", e.toString());
    }        

    return json;
}

public static String convertStreamToString(InputStream is) {

    BufferedReader reader = new BufferedReader(new InputStreamReader(is));
    StringBuilder sb = new StringBuilder();

    String line = null;
    try 
    {
        while ((line = reader.readLine()) != null) 
        {
            sb.append(line + "\n");
        }
    } 
    catch (IOException e) 
    {
        e.printStackTrace();
        Log.i("Error: ", e.toString());
    } 
    finally 
    {
        try 
        {
            is.close();
        } 
        catch (IOException e) 
        {
            e.printStackTrace();
        }
    }
    return sb.toString();
}