[英]Hibernate hql inner join eager fetch on one to many, fetching redundant parent objects
我有如下實體
類ProgressNote
@Entity
public class ProgressNote implements Serializable{
@Id
private NotesKey notesKey = new NotesKey();
private Set<PatientObjective> patientObjectives;
public NotesKey getNotesKey() {
return notesKey;
}
public void setNotesKey(NotesKey notesKey) {
this.notesKey = notesKey;
}
@OneToMany(fetch=FetchType.LAZY)
@Access(AccessType.PROPERTY)
@JoinColumns({
@JoinColumn(name="noteNumber",referencedColumnName="noteNumber"),
@JoinColumn(name="ddate",referencedColumnName="ddate"),
@JoinColumn(name="patient_id",referencedColumnName="patient_id")
})
public Set<PatientObjective> getPatientObjectives() {
return patientObjectives;
}
public void setPatientObjectives(Set<PatientObjective> patientObjectives) {
this.patientObjectives = patientObjectives;
}
}
類NotesKey
@Embeddable
public class NotesKey implements Serializable{
private Byte noteNumber;
@Temporal(javax.persistence.TemporalType.DATE)
@Column(name="ddate")
private Date noteDate;
private Patient patient;
public Byte getNoteNumber() {
return noteNumber;
}
public void setNoteNumber(Byte noteNumber) {
this.noteNumber = noteNumber;
}
public Date getNoteDate() {
return noteDate;
}
public void setNoteDate(Date noteDate) {
this.noteDate = noteDate;
}
@ManyToOne(fetch=FetchType.LAZY)
@Access(AccessType.PROPERTY)
public Patient getPatient() {
return patient;
}
public void setPatient(Patient patient) {
this.patient = patient;
}
@Override
public int hashCode() {
........
}
@Override
public boolean equals(Object obj) {
........
}
}
類PatientObjective
@Entity
public class PatientObjective implements Serializable{
@Id
private PatientObjectiveKey patientObjectiveKey;
public PatientObjectiveKey getPatientObjectiveKey() {
return patientObjectiveKey;
}
public void setPatientObjectiveKey(PatientObjectiveKey patientObjectiveKey) {
this.patientObjectiveKey = patientObjectiveKey;
}
}
類PatientObjectiveKey
@Embeddable
public class PatientObjectiveKey implements Serializable{
private Objective objective;
private Byte noteNumber;
@Temporal(javax.persistence.TemporalType.DATE)
@Column(name="ddate")
private Date noteDate;
private Patient patient;
@ManyToOne(fetch=FetchType.LAZY)
@Access(AccessType.PROPERTY)
public Objective getObjective() {
return objective;
}
public void setObjective(Objective objective) {
this.objective = objective;
}
public Byte getNoteNumber() {
return noteNumber;
}
public void setNoteNumber(Byte noteNumber) {
this.noteNumber = noteNumber;
}
public Date getNoteDate() {
return noteDate;
}
public void setNoteDate(Date noteDate) {
this.noteDate = noteDate;
}
@ManyToOne(fetch=FetchType.LAZY)
@Access(AccessType.PROPERTY)
public Patient getPatient() {
return patient;
}
public void setPatient(Patient patient) {
this.patient = patient;
}
@Override
public int hashCode() {
.......
}
@Override
public boolean equals(Object obj) {
........
}
}
我使用這個命名查詢后
@NamedQuery(name =“findAllProgressNoteWithObjective”,query =“from ProgressNote p inner join fetch p.patientObjectives as o where p.notesKey.patient.id =:patientId)”)使用spring hibernate模板findByNamedQueryAndNamedParam
在表I中有2個ProgressNotes,其中一個具有單個目標,另一個具有17個目標。 我在Java中得到如下結果。
查詢生成為
select progressno0_.ddate as ddate46_0_, progressno0_.noteNumber as noteNumber46_0_, progressno0_.patient_id as patient17_46_0_, patientobj1_.ddate as ddate36_1_, patientobj1_.noteNumber as noteNumber36_1_, patientobj1_.objective_id as objective5_36_1_, patientobj1_.patient_id as patient6_36_1_, progressno0_.assessment as assessment46_0_, progressno0_.bloodPressure1 as bloodPre4_46_0_, progressno0_.bloodPressure2 as bloodPre5_46_0_, progressno0_.creationDate as creation6_46_0_, progressno0_.height as height46_0_, progressno0_.lastUpdatedDate as lastUpda8_46_0_, progressno0_.plans as plans46_0_, progressno0_.status as status46_0_, progressno0_.subject as subject46_0_, progressno0_.temprature as temprature46_0_, progressno0_.tempratureUnit as temprat13_46_0_, progressno0_.lastid as lastid46_0_, progressno0_.waist as waist46_0_, progressno0_.weight as weight46_0_, progressno0_.weightUnit as weightUnit46_0_, patientobj1_.remark as remark36_1_, patientobj1_.value as value36_1_, patientobj1_.ddate as ddate46_0__, patientobj1_.noteNumber as noteNumber46_0__, patientobj1_.patient_id as patient6_46_0__, patientobj1_.ddate as ddate0__, patientobj1_.noteNumber as noteNumber0__, patientobj1_.objective_id as objective5_0__, patientobj1_.patient_id as patient6_0__ from pnheader progressno0_ inner join pnobjremark patientobj1_ on progressno0_.ddate=patientobj1_.ddate and progressno0_.noteNumber=patientobj1_.noteNumber and progressno0_.patient_id=patientobj1_.patient_id where progressno0_.patient_id=?
題
問題我看到為什么我得到ProgressNote的多個單個實例(id = 152)。有沒有辦法可以避免這種重復?
如果有人解釋或指出我正確的方向,我將非常感激。
使用Hibernate 3.6,Mysql 5.6.10
使用不同:
select distinct p from ProgressNote p
inner join fetch p.patientObjectives as o
where p.notesKey.patient.id = :patientId)
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