如何在python中對元組列表進行排序？

Question

如何在python中對元組列表進行排序

例如：請注意，元組的最后一個元素是相同的

a  = [

[(1, 5, 6), (2, 2, 6), (3, 6, 6)],
[(6, 1, 3), (5, 7, 3), (4, 1, 3)],
[(5, 7, 2), (7, 5, 2), (6, 3, 2)],
[(9, 1, 7), (1, 5, 7), (2, 6, 7)]

]

我想使用元組的最后一個元素作為鍵進行排序。 所以預期的結果是

[

[(5, 7, 2), (7, 5, 2), (6, 3, 2)],
[(6, 1, 3), (5, 7, 3), (4, 1, 3)],
[(1, 5, 6), (2, 2, 6), (3, 6, 6)],
[(9, 1, 7), (1, 5, 7), (2, 6, 7)]

]

Answer 1

In [27]: a  = [
   ....:
   ....: [(1, 5, 6), (2, 2, 6), (3, 6, 6)],
   ....: [(6, 1, 3), (5, 7, 3), (4, 1, 3)],
   ....: [(5, 7, 2), (7, 5, 2), (6, 3, 2)],
   ....: [(9, 1, 7), (1, 5, 7), (2, 6, 7)]
   ....:
   ....: ]
                               # any tuple (first will do), last element
In [28]: a.sort(key=lambda l: l[0][-1])

In [29]: a
Out[29]:
[[(5, 7, 2), (7, 5, 2), (6, 3, 2)],
 [(6, 1, 3), (5, 7, 3), (4, 1, 3)],
 [(1, 5, 6), (2, 2, 6), (3, 6, 6)],
 [(9, 1, 7), (1, 5, 7), (2, 6, 7)]]

Answer 2

使用key參數進行排序和使用lambda函數

a.sort(key=lambda x: x[-1][-1]). # sorts in-place
sorted(a, key=lambda x: x[-1][-1]). # new sorted list

編輯 ：根據要比較的元組來更改第一個索引。 即，使用x[0][-1]根據第一個元組進行比較