Android SQLite查詢ContentProvider Case語句語法

Question

我在運行此查詢時收到錯誤，是否知道我的語法錯誤是什么？

final Cursor c = getContentResolver().query(
Provider.GAME_URI, new String[]{"CASE WHEN " +DBHelper.COLUMN_CRE_USER + " = " + preferences.getInt(LoginScreen.ID, 0) + " THEN (" + DBHelper.COLUMN_CRE_PTS + " AS you AND " + DBHelper.COLUMN_CON_PTS + " AS them) ELSE (" + DBHelper.COLUMN_CON_PTS + " AS you AND " + DBHelper.COLUMN_CRE_PTS + " AS them)"},"turn = ?",
new String[] { preferences.getInt(LoginScreen.ID, 0) + ""}, null);

04月24日19：57：48.345：E / AndroidRuntime（18775）：由以下原因引起：android.database.sqlite.SQLiteException：在“ AS”附近：語法錯誤（代碼1）：，而在編譯時：創建CASE時創建了SELECT ASE = 112 THEN （創建的玩家和您所連接的玩家一樣）ELSE（創建的玩家和您所創建的玩家一樣）來自游戲在哪里（turn =？）

Answer 1

嘗試這個。

SELECT 
    CASE WHEN createduser = 112 THEN createdplayerpts ELSE connectedplayerpts END AS you,
    CASE WHEN createduser = 112 THEN connectedplayerpts ELSE createdplayerpts END AS them
FROM 
    game WHERE (turn = ?)