[英]Conditional sum in Group By query MSSQL
我有一個表OrderDetails與以下架構:
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| OrderId | CopyCost | FullPrice | Price | PriceType |
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| 16 | 50 | 100 | 50 | CopyCost |
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| 16 | 50 | 100 | 100 | FullPrice |
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| 16 | 50 | 100 | 50 | CopyCost |
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| 16 | 50 | 100 | 50 | CopyCost |
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我需要一個查詢,將上面的表推測為具有以下模式的新表:
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| OrderId | ItemCount | TotalCopyCost | TotalFullPrice |
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| 16 | 4 | 150 | 100 |
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目前我在Order.Id上使用Group By來計算項目數。 但我不知道如何有條理地推測CopyCost和FullPrice值。
任何幫助將非常感激。
關心弗雷迪
嘗試
SELECT OrderId,
COUNT(*) ItemCount,
SUM(CASE WHEN PriceType = 'CopyCost' THEN Price ELSE 0 END) TotalCopyCost,
SUM(CASE WHEN PriceType = 'FullPrice' THEN Price ELSE 0 END) TotalFullPrice
FROM OrderDetails
GROUP BY OrderId
試試這個查詢
select
orderId,
count(*) as cnt,
sum(if(pricetype='CopyCost', CopyCost, 0)) as totalCopyCost,
sum(if(pricetype='FullPrice', FullPrice, 0)) as totalFullPrice
from
tbl
group by
orderId
| ORDERID | CNT | TOTALCOPYCOST | TOTALFULLPRICE |
--------------------------------------------------
| 16 | 4 | 150 | 100 |
你能用:
SELECT
OrderId,
Count(1) as ItemCount,
SUM(CASE WHEN PriceType = 'CopyCost'
THEN CopyCost ELSE 0 END) AS TotalCopyCost,
SUM(CASE WHEN PriceType = 'FullPrice'
THEN FullPrice ELSE 0 END) AS TotalFullPrice
FROM OrderDetails
GROUP BY OrderId
你也可以試試......
select A.OrderID, A.ItemCount,B.TotalCopyCost, C.TotalFullPrice
from (select OrderID, count(*) as ItemCount from orderdetails) as A,
(select OrderID, sum(CopyCost) as TotalCopyCost from orderdetails where PriceType = 'CopyCost') as B,
(select OrderID, sum(FullPrice) as TotalFullPrice from orderdetails where PriceType = 'FullPrice') as C
where A.OrderID = B.OrderID
SQLFiddle: http ://sqlfiddle.com/#!2/946af/6
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