[英]Populate 2nd dropdown based on 1st dropdown selected in PHP
我正在使用PHP和Postgresql / PostGIS數據庫。 我的數據庫架構是這樣的。
我正在使用以下代碼
<?php
$con = pg_connect("Connection Parameter");
if (!$con)
{
die("Could not connect: " . pg_last_error());
}
$divquery = "SELECT DISTINCT divname FROM union_bgd
ORDER BY divname";
$distquery = "SELECT DISTINCT distname FROM union_bgd
ORDER BY distname";
$resultDiv = pg_query($con, $divquery);
$resultDist = pg_query($con, $distquery);
?>
Division
<select id="division" name="division" onclick = "">
<option value="" selected="selected">Select a Division</option>
<?php
while($dd1 = pg_fetch_array( $resultDiv ))
{
echo '<option value= "' . $dd1['divname'] . '">' . $dd1['divname'] . '</option>';
}
?>
</select></br>
District
<select id="district" name="district" onclick = "">
<option value="" selected="selected">Select a District</option>
<?php
while($dd2 = pg_fetch_array( $resultDist ))
{
echo '<option value= "' . $dd2['distname'] . '">' . $dd2['distname'] . '</option>';
}
?>
</select>
<?php
pg_close($con);
?>
當前,它在下拉列表中填充所有divname和distname,但我想如果選擇“ Dhaka”,則僅在dhaka下的distname將顯示在第二個下拉列表中。
謝謝
應該有where
子句
$distquery = "SELECT DISTINCT distname FROM union_bgd ORDER BY distname";
像這樣編輯
$distquery = "SELECT DISTINCT distname FROM union_bgd where divname=".$selected_dist." ORDER BY distname";
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