用python字符串中的另一個單詞替換單詞

Question

我有一個字符串： "y, i agree with u."

我有數組字典[(word_will_replace, [word_will_be_replaced])] ：

[('yes', ['y', 'ya', 'ye']), ('you', ['u', 'yu'])]

我想根據數組字典將“ y”替換為“ yes” ，將“ u”替換為“ you” 。

所以我想要的結果"yes, i agree with you." ： "yes, i agree with you."

我想在那里保留標點符號。

Answer 1

import re
s="y, i agree with u. yu."
l=[('yes', ['y', 'ya', 'ye']), ('you', ['u', 'yu'])] 
d={ k : "\\b(?:" + "|".join(v) + ")\\b" for k,v in l}
for k,r in d.items(): s = re.sub(r, k, s)  
print s

輸出量

yes, i agree with you. you.

Answer 2

從“ 替換子字符串”擴展了@gnibbler的答案，其中給出了要替換的字符串字典作為鍵，將替換字符串作為值。 Python和Raymond Hettinger在注釋中實現的技巧。

import re
text = "y, i agree with u."
replacements = [('yes', ['y', 'ya', 'ye']), ('you', ['u', 'yu'])]
d = {w: repl for repl, words in replacements for w in words}
def fn(match):
    return d[match.group()]

print re.sub('|'.join(r'\b{0}\b'.format(re.escape(k)) for k in d), fn, text)

---

>>> 
yes, i agree with you.

Answer 3

那不是字典-而是列表，但是可以很容易地將其轉換成dict 。 但是，在這種情況下，我將使其更加明確：

d = {}
replacements = [('yes', ['y', 'ya', 'ye']), ('you', ['u', 'yu'])]
for value,words in replacements:
    for word in words:
        d[word] = value

現在，您有了字典映射響應，可以將其替換為：

{'y':'yes', 'ya':'yes', 'ye':'yes',...}

一旦有了，就可以使用正則表達式從這里彈出我的答案： https : //stackoverflow.com/a/15324369/748858