[英]How to replace default leaflet.control to the set of individual buttons
[英]How to properly set id for individual mouseover buttons
我有一列按鈕,它們的作用必須與第一個按鈕相同,但是要有自己的個人照片。 我該如何設置ID以便不出現故障? 現在,我設置了三個按鈕,但是它們以某種方式復制了相同的名稱(它們都表示移動快速清洗)! 這是到目前為止我所擁有的http://ultimatefinishdetailing.com/Services.html
HTML :(在圖像按鈕之前發布HTML)
<STYLE MEDIA="screen" TYPE="text/css">
.pop-up {
height: 100px;
width: 100px;
margin-right: -100px;
margin-top: -100px;
position:absolute;
right:-50px;
top:75px;
}
.button {
width:300px;
height:21px;
display:block; background-image:url(images/button_ufad4.jpg);
position:absolute;
}
</style>
<a href="" class="button" onmouseover="javascript:ShowImage('images/InteriorandExteriorDetailing.jpg')" onmouseout="javascript:HideImage()"></a>
<div id="popup" class="pop-up">
<img id="popupImage" alt="" />
</div>
Javascript:
<script type="text/javascript">
function ShowImage(src)
{
var img = document.getElementById('popupImage');
var div = document.getElementById('popup');
img.src = src;
div.style.display = "block";
}
function HideImage()
{
document.getElementById('popup').style.display = "none";
}
</script>
弄清楚了! 為每個按鈕使用不同的ID,類。 下面的示例是一個按鈕,每隔一個按鈕更改ID /類的數量
HTML:1. CSS(樣式)必須具有自己的ID EX :(。pop-up1,2,3等; .button1,2,3等)2. <A>
(錨標記)必須具有自己的ID和類EX:(ID = BUTTON1,2,3等; CLASS = button1,2,3等)3. div標簽<div>
必須具有其自己的ID,類,圖像id EX:(DIV ID =“ popup1”,CLASS =“ pop-up1”,IMG ID =“ popupImage1
<STYLE MEDIA="screen" TYPE="text/css">
.pop-up1 {height: 100px;width: 100px;margin-right:-100px;margin-top:-100px;position:absolute;display:none;right:-50px;top: 75px;opacity:.7;z-index: 1}
.button1 {
width:300px;
height:21px;
display:block; background-image:url(images/button_ufad4.gif);
position:absolute;
}
.button1:hover { background-position:left 43px;
}
</STYLE>
<A ID="BUTTON1" HREF="" CLASS="button1" ONMOUSEOVER="javascript:ShowImage('images/ufad2servicesexteriorandinteriordetailing.gif')" ONMOUSEOUT="javascript:HideImage()"></A>
<DIV ID="popup1" CLASS="pop-up1">
<IMG ID="popupImage1">
</DIV>
Javascript:
<script type="text/javascript">
function ShowImage(src)
{
var img= document.getElementById('popupImage1');
var div= document.getElementById('popup1');
img.src=src;
div.style.display="block";
}
function HideImage()
{ document.getElementById('popup1').style.display ="none";}
</script>
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.