[英]how to count mysql records for each month of the year grouped by one field
我一直在審查一些實例,但沒有找到我需要的。 該查詢顯示按月分組的每個代理商的記錄數。 這是我的表結構的一部分:
recid | agency_id | departure_date
因此,我需要按代理商和月份(“ department_date”的月份)來計算“收據”組,並獲得總
Agency_id | JAN | FEB | MAR | APR | MAY | ........ | TOTAL
10 100 80 100 120 100 1200
看起來很容易。 但我找不到解決辦法。 任何幫助將不勝感激!
嘗試
SELECT agency_id,
SUM(CASE WHEN MONTH(departure_date) = 1 THEN 1 ELSE 0 END) Jan,
SUM(CASE WHEN MONTH(departure_date) = 2 THEN 1 ELSE 0 END) Feb,
SUM(CASE WHEN MONTH(departure_date) = 3 THEN 1 ELSE 0 END) Mar,
...
COUNT(*) Total
FROM table1
WHERE departure_date BETWEEN '2013-01-01' AND '2013-12-31'
GROUP BY agency_id
輸出:
| AGENCY_ID | JAN | FEB | MAR | APR | MAY | JUN | JUL | AUG | SEP | OCT | NOV | DEC | TOTAL |
---------------------------------------------------------------------------------------------
| 1 | 1 | 1 | 1 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 3 |
| 2 | 2 | 2 | 1 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 5 |
| 3 | 0 | 0 | 2 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 2 |
嘗試
select agency_id,
sum(if(month(`departure_date`) = 1,1,0)) as 'JAN',
sum(if(month(`departure_date`) = 2,1,0)) as 'FEB',
sum(if(month(`departure_date`) = 3,1,0)) as 'MAR',
sum(if(month(`departure_date`) = 4,1,0)) as 'APR',
sum(if(month(`departure_date`) = 5,1,0)) as 'MAY',
sum(if(month(`departure_date`) = 6,1,0)) as 'JUN',
sum(if(month(`departure_date`) = 7,1,0)) as 'JULY',
sum(if(month(`departure_date`) = 8,1,0)) as 'AUG',
sum(if(month(`departure_date`) = 9,1,0)) as 'SEPT',
sum(if(month(`departure_date`) = 10,1,0)) as 'OCT',
sum(if(month(`departure_date`) = 11,1,0)) as 'NOV',
sum(if(month(`departure_date`) = 12,1,0)) as 'DEC',
count(agency_id) as TOTAL
from tablename
where .....
group by agency_id
試試看:
SELECT
agency_id,
SUM(IF(month = 1, numRecords, NULL)) AS 'January',
SUM(IF(month = 2, numRecords, NULL)) AS 'Feburary',
SUM(IF(month = 3, numRecords, NULL)) AS 'March',
SUM(IF(month = 4, numRecords, NULL)) AS 'April',
SUM(IF(month = 5, numRecords, NULL)) AS 'May',
SUM(IF(month = 6, numRecords, NULL)) AS 'June',
SUM(IF(month = 7, numRecords, NULL)) AS 'July',
SUM(IF(month = 8, numRecords, NULL)) AS 'August',
SUM(IF(month = 9, numRecords, NULL)) AS 'September',
SUM(IF(month = 10, numRecords, NULL)) AS 'October',
SUM(IF(month = 11, numRecords, NULL)) AS 'November',
SUM(IF(month = 12, numRecords, NULL)) AS 'December',
SUM(numRecords) AS total
FROM (
SELECT agency_id, month(departure_date) AS month, count(*) as numRecords
FROM your_table_name
GROUP BY agency_id, month
) AS SubTable1 GROUP BY agency_id
對於特定的agency_id沒有記錄的月份,此查詢將顯示null
。 如果要將其顯示為0
,請更新查詢並將NULL
替換為文字0
。
看看帶有ROLLUP子句的解決方案,它顯示了您所需要的,但是給出了另一個輸出-
SELECT
agency_id, MONTH(departure_date) month, COUNT(*) count
FROM
sales
GROUP BY
agency_id, MONTH(departure_date) WITH ROLLUP
WHERE
YEAR(departure_date) = 2013
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