HasMany的Yii關系數據問題

Question

當前，我們有兩個表。 地點和地址

位置與addresss.location_id上的地址是一對多關系。

我們正在嘗試輸出與cgridview中特定位置相關的所有地址：

admin.php

<?php $this->widget('zii.widgets.grid.CGridView', array(
    'id'=>'locations-grid',
    'dataProvider'=>$location->search(),
    'filter'=>$location,
    'columns'=>array(
        'id',
        'name',
        array(
            'name' => 'address',
            'value' => 'implode("<br>",CHtml::listData($data->addresses(),"id","address"))',
            'filter' => CHtml::activeTextField($location, 'address'),
            'type' => 'html',
        ),/**/  
        array(
            'class'=>'CButtonColumn',
        ),
    ),
)); ?>

模型（locations.php）

public function search()
    {
        // Warning: Please modify the following code to remove attributes that
        // should not be searched.
        $criteria=new CDbCriteria;
        $criteria->together = true;
        $criteria->with = array('addresses');
        $criteria->compare('id',$this->id);
        $criteria->compare('name',$this->name,true);
        $criteria->compare('addresses.address',$this->address,true);

        return new CActiveDataProvider($this, array(
            'criteria'=>$criteria,
        ));
    }

有沒有更好的方法來獲取地址數據而不是內嵌$ data-> addresses函數？

Answer 1

您可以將getter方法添加到Locations模型中。

public function getAddressNames($separator='<br>')
{
    $names = array();
    foreach($this->adresses as $address) {
        $names[] = $address->address;
    }
    return implode($separator, $names);
}

然后，您可以在gridview中使用類似於常規屬性的addressNames 。