如何解決開/關JavaScript

Question

我的on / off開關有問題。我有一個代碼無法正常工作，因為當我以表格形式編寫check時它可以工作，但是我想拖拉心情，on and off，當不寫檢查時它的形式不起作用，當我在兩者中都簽入時，它不起作用，當我在其中之一中簽入時，它起作用但不正確。:(

<script>  
function DisEn(X){  
  document.A.T1.disabled=X;
  document.A.T2.disabled=X;

}  
</script>
</head>
 <form name="A" method="get" action="switch.php">
    <div class="onoffswitch">
<input type="checkbox" name="onoffswitch" value="off" class="onoffswitch-checkbox" 
        id="myonoffswitch" onClick="DisEn(false)" checked>
   <input type="checkbox" name="onoffswitch" value="on" class="onoffswitch-checkbox" 
   id="myonoffswitch1" onClick="DisEn(false)" >

<label class="onoffswitch-label" for="myonoffswitch">
<div class="onoffswitch-inner"></div>
<div class="onoffswitch-switch"></div>
</label>

</div>
<input type="text" name="T1" value="A" disabled>  
  <input type="text" name="T2" value="B" disabled>

<input type="submit" name="T4" value="Submit" >   
</form>

Answer 1

使用onchange = DisEn(this)例如以下示例：

<script>  
    function DisEn(element){  
       if (element.checked === true) {
          document.A.T1.disabled=true;
          document.A.T2.disabled=true;
          element.value="off";
       } else {
          document.A.T1.disabled=false;
          document.A.T2.disabled=false;
          element.value="on";
       }
    }  
</script>
<form name="A" method="get" action="switch.php">
    <div class="onoffswitch">
        <input type="checkbox" name="onoffswitch" value="off" 
            class="onoffswitchcheckbox" id="myonoffswitch"
            onchange="DisEn(this)" checked = "checked" />
        <label class="onoffswitch-label" for="myonoffswitch">
            <div class="onoffswitch-inner"></div>
            <div class="onoffswitch-switch"></div>
        </label>
    </div>
    <input type="text" name="T1" value="A" disabled = "disabled" />
    <input type="text" name="T2" value="B" disabled = "disabled" />
    <input type="submit" name="T4" value="Submit" />
</form>

您可以在此處查看演示 。 如果出現問題或忘記做某事，請通知我，然后更新演示。

使用此功能，您只需在復選框上使用onchange = DisEn(this)以為每個復選框進行設置。

Answer 2

HTML：

<form name="A" method="get" action="switch.php">
    <div class="onoffswitch">
<input type="checkbox" name="onoffswitch" value="off"class="onoffswitchcheckbox"    
   id="myonoffswitch" onClick="DisEn()" checked> 


<label class="onoffswitch-label" for="myonoffswitch">
<div class="onoffswitch-inner"></div>
<div class="onoffswitch-switch"></div>
</label>

</div>
<input type="text" name="T1" value="A" disabled>  
  <input type="text" name="T2" value="B" disabled>

 <input type="submit" name="T4" value="Submit" >      
 </form>

Javascript：

function DisEn(){  

    if(document.A.onoffswitch.checked == false)
    {
  document.A.T1.disabled=false;
  document.A.T2.disabled=false;
    }
    else
    {
  document.A.T1.disabled=true;
  document.A.T2.disabled=true;
    }


}  

這是jsfiddle >> http://jsfiddle.net/YgWku/