無法獲取更新mysql記錄的表單

Question

我有一個像這樣工作的三部分表單，第一個表單叫做create_ticket.php，它基本上是一個帶有客戶聯系信息和他們想要做的事情的表單。 當票據填寫完畢后，它會被提交給MySQL，然后當搜索完db時，您可以通過單擊搜索結果中與該票證相關聯的選擇鏈接來選擇所需的票證，瀏覽器將打開一個新窗口。表單的第二部分但是它會在瀏覽器中傳遞與MySQL記錄關聯的id，所以你在url的末尾看到了id = 10現在表單的第二部分是技術人員用來填寫什么的他們這樣做，當他們點擊頁面底部的簽名時，它會彈出表格的第3部分，允許客戶在技術的ipad或Toughbook上簽名，當他們點擊接受時，它應該更新與MySQL相關的記錄該ID在網址中傳遞。 我的問題是它不起作用。 所以你可以在http://jemtechnv.com/test/ticket_results.php查看表格，看看當你點擊選擇它時會帶你到技術人員表格填寫。 這是我處理表單第二部分的代碼：

<?php
// database connection //

include 'db/db_connect.php';

//This gets all the other information from the form

// start of form inputs //

$work_performed=$_POST['work_performed'];
$item_qty1=$_POST['item_qty1'];
$item_qty2=($_POST['item_qty2']);
$item_qty3=$_POST['item_qty1'];
$item_qty4=($_POST['item_qty2']);
$item_qty5=$_POST['item_qty1'];
$manuf_1=$_POST['manuf_1'];
$manuf_2=$_POST['manuf_2'];
$manuf_3=$_POST['manuf_3'];
$manuf_4=$_POST['manuf_4'];
$manuf_5=$_POST['manuf_5'];
$part_number1=$_POST['part_number1'];
$part_number2=$_POST['part_number2'];
$part_number3=$_POST['part_number3'];
$part_number4=$_POST['part_number4'];
$part_number5=$_POST['part_number5'];
$part_description1=$_POST['part_description1'];
$part_description2=$_POST['part_description2'];
$part_description3=$_POST['part_description3'];
$part_description4=$_POST['part_description4'];
$part_description5=$_POST['part_description5'];
$part1_price=$_POST['part_price1'];
$part2_price=$_POST['part_price2'];
$part3_price=$_POST['part_price3'];
$part4_price=$_POST['part_price4'];
$part5_price=$_POST['part_price5'];
$price_extension1=$_POST['price_extension1'];
$price_extension2=$_POST['price_extension2'];
$price_extension3=$_POST['price_extension3'];
$price_extension4=$_POST['price_extension4'];
$price_extension5=$_POST['price_extension5'];
$material_total=$_POST['material_total'];
$sales_tax=$_POST['sales_tax'];
$shipping_cost=$_POST['shipping_cost'];
$work_date1=$_POST['work_date1'];
$work_date2=$_POST['work_date2'];
$work_date3=$_POST['work_date3'];
$work_date4=$_POST['work_date4'];
$work_date5=$_POST['work_date5'];
$tech_name1=$_POST['tech_name1'];
$tech_name2=$_POST['tech_name2'];
$tech_name3=$_POST['tech_name3'];
$tech_name4=$_POST['tech_name4'];
$tech_name5=$_POST['tech_name5'];
$cost_code1=$_POST['cost_code1'];
$cost_code2=$_POST['cost_code2'];
$cost_code3=$_POST['cost_code3'];
$cost_code4=$_POST['cost_code4'];
$cost_code5=$_POST['cost_code5'];
$pay_rate1=$_POST['pay_rate1'];
$pay_rate2=$_POST['pay_rate2'];
$pay_rate3=$_POST['pay_rate3'];
$pay_rate4=$_POST['pay_rate4'];
$pay_rate5=$_POST['pay_rate5'];
$total_hours1=$_POST['total_hours1'];
$total_hours2=$_POST['total_hours2'];
$total_hours3=$_POST['total_hours3'];
$total_hours4=$_POST['total_hours4'];
$total_hours5=$_POST['total_hours5'];
$hours_subtotal1=$_POST['hours_subtotal1'];
$hours_subtotal2=$_POST['hours_subtotal2'];
$hours_subtotal3=$_POST['hours_subtotal3'];
$hours_subtotal4=$_POST['hours_subtotal4'];
$hours_subtotal5=$_POST['hours_subtotal5'];
$total_hours=$_POST['total_hours'];
$material_total=$_POST['material_total'];
$labor_cost=$_POST['labor_cost'];
$grand_total=$_POST['grand_total'];

//Writes the information to the database
 mysql_query("UPDATE INTO tickets WHERE id=$id (work_performed, item_qty1, item_qty2, item_qty3, item_qty4, item_qty5,manuf_1, manuf_2, manuf_3, manuf_4, manuf_5, part_number1, part_number2, part_number3, part_number4, part_number5, part_description1, part_description2, part_description3, part_description_4, part_description_5, part1_price, part2_price, part3_price, part4_price, part5_price, price_extension1, price_extension2, price_extension3, price_extension4, price_extension5, material_total, sales_tax, shipping_cost, work_date1, work_date2, work_date3, work_date4, work_date5, tech_name1, tech_name2, tech_name3, tech_name4, tech_name5, cost_code1, cost_code2, cost_code3, cost_code4, cost_code5, pay_rate1, pay_rate2, pay_rate3, pay_rate4, pay_rate5, total_hours1, total_hours2, total_hours3, total_hours4, total_hours5, hours_subtotal1, hours_subtotal2, hours_subtotal3, hours_subtotal4, hours_subtotal5, total_hours, material_total, labor_cost, grand_total,)
VALUES ('$work_performed','$item_qty1','$item_qty2','$item_qty3','$item_qty4','$item_qty5','$mauf_1','$manuf_2','$manuf_3','$manuf_4','$manuf_5','$part_number1','$part_number2','$part_number3','$part_number4','$part_number5','$part_description1','$part_description2','$part_description3','$part_description_4',
'$part_description5','$part1_price','$part2_price','$part3_price','$part4_price','$part5_price','$price_extension1','$price_extension2','$price_extension3','$price_extension4','$price_extension5','$material_total','$sales_tax','$shipping_cost','$work_date1','$work_date2','$work_date3','$work_date4','$work_date5','$tech_name1','$tech_name2','$tech_name3','$tech_name4','$tech_name5','$cost_code1','$cost_code2','$cost_code3','$cost_code4','$cost_code5','$pay_rate1','$pay_rate2','$pay_rate3','$pay_rate4','$pay_rate5',
'$total_hours1','$total_hours2','$total_hours3','$total_hours4','$total_hours5','$hours_subtotal1','$hours_subtotal2','$hours_subtotal3','$hours_subtotal4','$hours_subtotal5','$total_hours','$material_total','$labor_cost','$grand_total',)") ; 



mysql_affected_rows();

    ?>
<html>
<body>
<center>
<br><br><br>
<form name="results" method="post" action="ticket_results.php" enctype="multipart/form-data" id="ticketresult">
<input type="submit" class="submit" id="ticketresult" style="width: 165px" value="Do Something">
</form>
</center>
</body>
</html>

我也知道我需要采取MySQL注入預防措施，但老實說，目前這不是一個優先事項，因為我只是想讓表單先工作，然后我會回去清理代碼。 謝謝你的幫助！ 我已經禁用了表單的簽名部分，因此點擊第二個表單上的get signature將處理表單並對該記錄進行更新，這應該是但不應該！

更新：我已經按照下面的建議更改了查詢語法：

mysql_query("UPDATE tickets SET (work_performed, item_qty1, item_qty2, item_qty3, item_qty4, item_qty5,manuf_1, manuf_2, manuf_3, manuf_4, manuf_5, part_number1, part_number2, part_number3, part_number4, part_number5, part_description1, part_description2, part_description3, part_description_4, part_description_5, part1_price, part2_price, part3_price, part4_price, part5_price, price_extension1, price_extension2, price_extension3, price_extension4, price_extension5, material_total, sales_tax, shipping_cost, work_date1, work_date2, work_date3, work_date4, work_date5, tech_name1, tech_name2, tech_name3, tech_name4, tech_name5, cost_code1, cost_code2, cost_code3, cost_code4, cost_code5, pay_rate1, pay_rate2, pay_rate3, pay_rate4, pay_rate5, total_hours1, total_hours2, total_hours3, total_hours4, total_hours5, hours_subtotal1, hours_subtotal2, hours_subtotal3, hours_subtotal4, hours_subtotal5, total_hours, material_total, labor_cost, grand_total,)WHERE id=$id
VALUES ('$work_performed','$item_qty1','$item_qty2','$item_qty3','$item_qty4','$item_qty5','$mauf_1','$manuf_2','$manuf_3','$manuf_4','$manuf_5','$part_number1','$part_number2','$part_number3','$part_number4','$part_number5','$part_description1','$part_description2','$part_description3','$part_description_4',
'$part_description5','$part1_price','$part2_price','$part3_price','$part4_price','$part5_price','$price_extension1','$price_extension2','$price_extension3','$price_extension4','$price_extension5','$material_total','$sales_tax','$shipping_cost','$work_date1','$work_date2','$work_date3','$work_date4','$work_date5','$tech_name1','$tech_name2','$tech_name3','$tech_name4','$tech_name5','$cost_code1','$cost_code2','$cost_code3','$cost_code4','$cost_code5','$pay_rate1','$pay_rate2','$pay_rate3','$pay_rate4','$pay_rate5',
'$total_hours1','$total_hours2','$total_hours3','$total_hours4','$total_hours5','$hours_subtotal1','$hours_subtotal2','$hours_subtotal3','$hours_subtotal4','$hours_subtotal5','$total_hours','$material_total','$labor_cost','$grand_total',)"); 

但是現在我提交表單來更新數據庫時出現以下錯誤，

您的SQL語法有錯誤; 查看與您的MySQL服務器版本對應的手冊，以便在'（work_performed，item_qty1，item_qty2，item_qty3，item_qty4，item_qty5，manuf_1，'第1行附近使用正確的語法

Answer 1

你的查詢錯了。 查詢應該是

UPDATE tickets  SET work_performed = something, item_qty1 = something .... WHERE id=$id