Java-Windows中FileUpload拋出錯誤的方法

Question

我想測試一個用於文件上傳的示例程序。但是它顯示錯誤“ FileNotFoundException”。

   import java.io.BufferedInputStream;
import java.io.BufferedOutputStream;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;



public class TestUpload {

    /**
     * @param args
     */
    public boolean handleFileUpload(){


        BufferedOutputStream bos = null;
        BufferedInputStream bis = null;
        boolean isFileUplodedCorrectly = true;
        try {
            bos = new BufferedOutputStream(new FileOutputStream(new File("D:\\vishu.jpeg")));
            bis = new BufferedInputStream(new FileInputStream(new File("D:\\vishuGreetings.jpeg")));


            byte[] b = new byte[1024];

            while (bis.read(b) != -1)
                bos.write(b);
            bos.flush();
        } catch (Exception e) {
            isFileUplodedCorrectly = false;
            e.printStackTrace();
            System.out.print("Exception in FileUpload Utils " + e);
        } finally {
            try {
                bos.close();

            } catch (IOException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }

        }
        return isFileUplodedCorrectly;

    }

public static void main(String[] args) {
        // TODO Auto-generated method stub
    TestUpload tu=new TestUpload();
    System.out.println("Status"+tu.handleFileUpload());

    }

}

實際上文件在那里。 請檢查。

    java.io.FileNotFoundException: D:\vishuGreetings.jpeg (The system cannot find the file specified)
    at java.io.FileInputStream.open(Native Method)
    at java.io.FileInputStream.<init>(FileInputStream.java:106)
    at TestUpload.handleFileUpload(TestUpload.java:23)
    at TestUpload.main(TestUpload.java:52)
Exception in FileUpload Utils java.io.FileNotFoundException: D:\vishuGreetings.jpeg (The system cannot find the file specified)Statusfalse

文件D：/vishuGreetings.jpeg在那里，但是我同樣遇到了文件未找到異常，請檢查提供的代碼並還原。

Answer 1

我通過提供.jpg而不是jpeg來解決問題，發現它可以正常工作。當我檢查文件的屬性是jpeg時。 這就是為什么我在代碼中的nmae文件中使用了擴展名jpeg的原因。麻煩您了。