按月對MySQL行進行分組，並將數據計算到每個月

Question

我有一個名為“results”的表，其中包含許多行和一個名為“timestamp”的列。

我想分組每個月的行數。 但對於他們中的每一個，我也想考慮前幾個月的行。

所以，如果我有

Jun/13
Jun/13
Jun/13
Jul/13
Jul/13
Jul/13
Jul/13
Jul/13
Aug/13
Aug/13
Aug/13
Aug/13
Aug/13
Aug/13
Aug/13

結果將是

3  Jun/13
8  Jul/13
15 Aug/13

這就是我現在所擁有的，但它不考慮前幾個月。

SELECT DATE_FORMAT(FROM_UNIXTIME(timestamp), '%e %b %Y'), COUNT(1) FROM results
GROUP BY DATE_FORMAT(FROM_UNIXTIME(timestamp), '%e %b %Y');

Answer 1

我得到了這個工作：

SELECT month, count, @total:=@total+count AS total
FROM (SELECT @total:=0) t STRAIGHT_JOIN
  (SELECT DATE_FORMAT(FROM_UNIXTIME(timestamp), '%e %b %Y') AS month, COUNT(*) AS count
  FROM results GROUP BY EXTRACT(YEAR_MONTH FROM FROM_UNIXTIME(timestamp))) AS m;

+------------+-------+-------+
| month      | count | total |
+------------+-------+-------+
| 1 Jun 2013 |     3 |     3 |
| 1 Jul 2013 |     5 |     8 |
| 1 Aug 2013 |     7 |    15 |
+------------+-------+-------+

Answer 2

以下解決方案應該是......

SELECT COUNT（1），DATE_FORMAT（timestamp，'％b /％y'）FROM results GROUP BY YEAR（timestamp），MONTH（timestamp）;

祝好運

Talki

Answer 3

如果我理解正確，這應該有效;

SELECT COUNT(*) num, SUBSTR(ts, 1, 7) month
FROM results
JOIN (SELECT MAX(timestamp) ts FROM results
      GROUP BY YEAR(timestamp),Month(timestamp)) mm
  ON results.timestamp <= mm.ts
GROUP BY SUBSTR(ts, 1, 7);

一個要測試的SQLfiddle 。