[英]How to get all value in php mysql in a ID?
我有一個樣本數據
product (ID, name)
1 | 'iPhone'
2 | 'iPad'
3 | 'iWatch'
product_meta (ID, product_id, meta_key, meta_value)
1 1 image iPhone.png
2 2 view 123
並使用查詢:
SELECT p.*, m.*
FROM product AS p
LEFT JOIN product_meta AS m ON m.product_id = p.ID
WHERE p.ID = 1
GROUP BY p.ID
如何獲得所有價值的結果是
product(ID, name, image, view) => 1 | iPhone | iPhone.png | 123
假設您的樣本數據不正確,並且您要嘗試對結果進行PIVOT
,則可以將MAX
與CASE
使用:
select p.id,
p.name,
max(case when pm.meta_key = 'image' then pm.meta_value end) image,
max(case when pm.meta_key = 'view' then pm.meta_value end) view
from product AS p
left join product_meta AS pm ON pm.product_id = p.ID
where p.ID = 1
group by p.ID
您可以像從其余查詢中選擇table1.column1,table2.column2一樣。
基於與sgeddes相同的假設:
SELECT p.id, p.name, mimage.meta_value, mview.meta_value
FROM product AS p
LEFT JOIN product_meta AS mimage
ON mimage.product_id = p.id AND mimage.meta_key = 'image'
LEFT JOIN product_meta AS mview
ON mview.product_id = p.id AND mview.meta_key = 'view'
WHERE p.id = 1
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