列數中的MySQL計數值

Question

我有一個colum package ，包含包ID 1, 2, 3, 4 。 現在我的查詢將選擇所有表stores_profile和stores_fee按日期和按月份和過濾器

以下是我的數據庫：

表：stores_profile

表：stores_fee

這是我當前的查詢：

<?php
$filter_date = '2013-04-01';

$result = mysql_query("SELECT sp.*, sf.*, sp.id as store_profile_id,DATE_FORMAT(sf.date_start, '%d-%m-%Y') as month
 FROM `stores_profile` sp
 left join `stores_fee` sf ON sp.id=sf.store_id 
 where sf.date_start >= '".$filter_date."' GROUP BY MONTH(sf.date_start) ");

while($row = mysql_fetch_array($result)) {
    $month = date('M', strtotime($row['month']));
    $package = $row['package']; 
?>
      <tr>
        <td><?php echo $month ?>&nbsp;</td>
        <td>&nbsp;</td>
        <td>&nbsp;</td>
        <td>&nbsp;</td>
        <td>&nbsp;</td>
      </tr>
<?php } echo '</table>'; ?>

和此代碼的結果是：

那么，如何計算列package包ID然后按月分組並根據包ID得到總數，我知道它有點令人困惑，但結果應如下所示：

Answer 1

您可以嘗試使用SUM和CASE ：

SELECT DATE_FORMAT(sf.date_start, '%d-%m-%Y') as `Month`,
       SUM(CASE WHEN sf.package = 1 THEN 1 ELSE 0 END) AS `Package 1`,
       SUM(CASE WHEN sf.package = 2 THEN 1 ELSE 0 END) AS `Package 2`,
       SUM(CASE WHEN sf.package = 3 THEN 1 ELSE 0 END) AS `Package 3`,
       SUM(CASE WHEN sf.package = 4 THEN 1 ELSE 0 END) AS `Package 4`
FROM `stores_profile` sp
LEFT JOIN `stores_fee` sf ON sp.id = sf.store_id 
WHERE sf.date_start >= '".$filter_date."' GROUP BY MONTH(sf.date_start)

我能想到的另一種方法是對它進行子查詢。

Answer 2

如果我正確理解您的要求，您需要一個支點：

SELECT 
    SUM(IF(sf.package=1,1,0)) as package_1,
    SUM(IF(sf.package=2,1,0)) as package_2,
    SUM(IF(sf.package=3,1,0)) as package_3,
    SUM(IF(sf.package=4,1,0)) as package_4,
    DATE_FORMAT(sf.date_start, '%d-%m-%Y') as `month`
 FROM 
    `stores_profile` sp
 LEFT JOIN  `stores_fee` sf 
    ON sp.id=sf.store_id 
 WHERE 
    sf.date_start >= '".$filter_date."' 
 GROUP BY 
    MONTH(sf.date_start)