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@XmlJavaTypeAdapter不起作用

[英]@XmlJavaTypeAdapter doesn't work

我收到了該錯誤http://jira.codehaus.org/browse/JACKSON-288 ,但是它說該錯誤應該已經在1.6.2版中修復。

我指的是很多線程,例如,
澤西島JSON和日期
如何通過XML將Date(ActionScript 3)轉換為java.util.Date?

我嘗試了1.12、1.14、1.17.1版,但都無法在我這邊工作。

@XmlRootElement(name="info")
@XmlAccessorType(XmlAccessType.NONE)
public class InfoVO  { 
    private int infoId;
    @XmlElement
    @XmlJavaTypeAdapter(DateAdapter.class)
    private Date createTime;
//...get/set

}

import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.Date;

import javax.ws.rs.WebApplicationException;
import javax.xml.bind.annotation.adapters.XmlAdapter;

public class DateAdapter extends XmlAdapter<String, Date> {

    private static final SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");

    @Override
    public String marshal(Date v) {
        return dateFormat.format(v);
    }

    @Override
    public Date unmarshal(String v) {
        try {
            return dateFormat.parse(v);
        } catch (ParseException e) {
            throw new WebApplicationException();
        }
    }
}


    <dependency>
        <groupId>javax.annotation</groupId>
        <artifactId>jsr250-api</artifactId>
        <version>1.0</version>
    </dependency>

但是根本無法調用DateAdapter並出現異常,

2013-06-12 11:11:13.363:WARN :: // xa / info / save / 12121:org.codehaus.jackson.map.JsonMappingException:無法從字符串值'2013-06構造java.util.Date實例-08 08:00:00':不是有效的表示形式(錯誤:無法解析日期“ 2013-06-08 08:00:00”:與任何標准格式都不兼容(“ yyyy-MM-dd'T' HH:mm:ss.SSSZ“,” yyyy-MM-dd'T'HH:mm:ss.SSS'Z'“,” EEE,dd MMM yyyy HH:mm:ss zzz“,” yyyy-MM-dd “))| 在[來源:java.io.StringReader@b0ff5e1; 第8行,第23列)(通過參考鏈:com.xchange.me.vo.InfoVO [“ createTime”])

我找到了根本原因,因為我添加了自定義的MessageBodyReader,

  @Provider
    @Consumes("application/json")
    public class CustomJsonReader<T> implements MessageBodyReader<T> {
        @Override
        public boolean isReadable(Class<?> type, Type genericType, Annotation[] annotations, MediaType mediaType) {
            return true;
        }

    @Override
    public T readFrom(Class<T> type, Type genericType, Annotation[] annotations, MediaType mediaType, MultivaluedMap<String, String> httpHeaders,
            InputStream entityStream) throws IOException, WebApplicationException {

        /*
         * Copy the input stream to String. Do this however you like. Here I use
         * Commons IOUtils.
         */
        StringWriter writer = new StringWriter();
        IOUtils.copy(entityStream, writer, "UTF-8");
        String json = writer.toString();

        /*
         * if the input stream is expected to be deserialized into a String,
         * then just cast it
         */
        if (String.class == genericType)
            return type.cast(json);

        /*
         * Otherwise, deserialize the JSON into a POJO type. You can use
         * whatever JSON library you want, here's a simply example using GSON.
         */
        ObjectMapper objectMapper = new ObjectMapper();
        return objectMapper.readValue(json, type);
    }
    }

因此,當接收到json數據時,總是進入readFrom方法,然后在該行中引發異常return objectMapper.readValue(json,type);

所以我認為根本原因是ObjectMapper.readValue忽略注釋@XmlJavaTypeAdapter

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