根據變量的存在創建一個SQL查詢（$ _POST）

Question

正如我在標題中所解釋的，我想在我的php頁面上創建一個sql查詢，以返回存在變量的函數的特定結果。 我在頁面頂部有一個表單，其中包含一些輸入（日期，名稱等），單擊后，將刷新頁面並顯示正確的結果。

目前，我的語法是：

if (isset($_POST['dated']) && $_POST['dated'] != null){
    $doleances = $bdd->prepare('SELECT * FROM doleance WHERE Priorite < 5 AND Date >= ? ORDER BY ID DESC');
    $doleances->execute(array($newDate));

}
else if (isset($_POST['dated']) && $_POST['dated'] != null && isset($_POST['datef']) && $_POST['datef'] != null){
    $doleances = $bdd->prepare('SELECT * FROM doleance WHERE Priorite < 5 AND Date BETWEEN ? AND ? ORDER BY ID DESC');
    $doleances->execute(array($newDate, $newDate2));
}
else if{...}
else if{...}
...

但我認為有一種更好的方法...預先感謝

Answer 1

您可以使用按需構建的方法：

// Create holders for the WHERE clauses and query parameters
$where = array(
  "Priorite < 5"  // this looks common across all queries?
);
$params = array();

// Now build it based on what's suppled:
if (!empty($_POST['dated'])){
  if (!empty($_POST['datef'])){
    // Add to the params list and include a WHERE condition
    $params['startdate'] = $_POST['dated'];
    $params['enddate'] = $_POST['datef'];
    $where[] = "Date BETWEEN :startdate AND :enddate";
  }
  else{
    // Add to the params list and include a WHERE condition
    $params['date'] = $_POST['dated'];
    $where[] = "Date >= :date";
  }
}
else if { ... }
else if { ... }

// Now build and execute the query based on what we compiled together
// from above.
$sql = "SELECT * FROM doleance "
     . (count($where) > 0 ? "WHERE " . implode(" AND ", $where) : "")
     . " ORDER BY ID DESC";
$doleances = $bdd->prepare($sql);
$doleances->execute($params);

Answer 2

首先創建可能發布的變量的數組：

$possibleArgs = array( 'dated', 'datef' );

然后遍歷每個$possibleArg並檢查相應的$_POST[possibleArg]是否為空。 如果不為空，則將其添加到謂詞中。