有效JSON無法與jQuery.parseJSON（）一起使用

Question

我正在將JSON字符串保存到文件中並嘗試將其讀回。 由於某種原因，它不會讀回。 jsonlint.com告訴我這是有效的JSON。

這是JSON字符串：

{"userdef":{"vlan10":{"dfault":{"down":{"rate":"876","ceil":"876"},"up":{"rate":"876","ceil":"876"}},"upsell":{"down":{"rate":"876","ceil":"876"},"up":{"rate":"876","ceil":"76"}}},"br0":{"dfault":{"down":{"rate":"798","ceil":"987"},"up":{"rate":"987","ceil":"987"}},"upsell":{"down":{"rate":"98","ceil":"987"},"up":{"rate":"987","ceil":"89"}}},"br1":{"dfault":{"down":{"rate":"3","ceil":"654"},"up":{"rate":"654","ceil":"63"}},"upsell":{"down":{"rate":"65","ceil":"4"},"up":{"rate":"646","ceil":"5"}}},"eth3":{"dfault":{"down":{"rate":"65","ceil":"7876"},"up":{"rate":"7657","ceil":"5"}},"upsell":{"down":{"rate":"7865","ceil":"7"},"up":{"rate":"7","ceil":"5"}}}}}

這是javascript / php代碼：

<?
if (file_exists('/tmp/qosconfig.conf'))
{
?>
var config = jQuery.parseJSON('<?=file_get_contents("/tmp/qosconfig.conf");?>');    
<?
}
?>

Answer 1

這是一種相當奇怪的方式。 如果您在PHP中可以使用JSON字符串，則可以將其作為對象文字輸出到javascript中，從而節省了解析步驟。

<?
if (file_exists('/tmp/qosconfig.conf')) {
    $json = file_get_contents('/tmp/qosconfig.conf');
?>
var config = <?php echo $json; ?>;    
<?
}
?>