如何使用jaxb解析xml

Question

嗨，我正在嘗試獲取xml數據..結構如下：....

<transport>
    <Journey>
    <JourneyPatternSection id ="JPS_13">
       <from> a</from>
       <to>b</to> 
    </JourneypatternSection>
        </Journey>
        <JourneyPattern id="JP_1_0">
                                <JourneyPatternSectionRefs>JPS_13</JourneyPatternSectionRefs>
                        </JourneyPattern>
        <VechileJourney>
        <JourneyPatternRef>JP_1_0</JourneyPatternRef>
                    <DepartureTime>17:10:00</DepartureTime>
    </VechileJourney>
</transport>

我已經使用jaxb提取了JourneypatternId，但是由於vechilejourney標簽中的旅程模式id有所反映，因此我無法獲取出發時間和往返信息。

Answer 1

從http://www.thaiopensource.com/relaxng/trang-manual.html下載trang.jar轉到命令提示符，要將xml轉換為xsd，請鍵入以下命令

java -jar trang.jar transport.xml transport.xsd

將您的xml結構轉換為xsd，並編寫以下命令后，

xjc -p com.jaxb.test.xml.beans transport.xsd

上面的命令將從您的transport.xsd中生成Java bean

之后，您可以如下解組XML

try
    {
        final JAXBContext jc = JAXBContext.newInstance(Transport.class);
        final Unmarshaller unmarshaller = jc.createUnmarshaller();
        try
        {
            final Transport transport = (Transport) unmarshaller.unmarshal(new FileReader(TRANSPORT_XML));
        } catch (final FileNotFoundException e)
        {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
    } catch (final JAXBException e)
    {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

參考： http ： //shahpritesh.blogspot.in/2012/06/writing-and-reading-java-object-to-and.html