Android .apk文件未完全從.Net Server下載。 在手機中獲取程序包解析錯誤

Question

    using System;
using System.Collections.Generic;

using System.Web;
using System.Web.UI;
using System.Web.UI.WebControls;

public partial class HomePanel : System.Web.UI.Page
{
    protected void Page_Load(object sender, EventArgs e)
    {

    }
    protected void LinkButton1_Click(object sender, EventArgs e)
    {
        DownloadFile();
    }
    protected void ImageButton1_Click(object sender, ImageClickEventArgs e)
    {
        DownloadFile();
    }
    private void DownloadFile()
    {
        string getPath = "E-MobApps/Sab Recharge.apk";
        System.IO.Stream iStream = null;

        // Buffer to read 10K bytes in chunk:
        byte[] buffer = new Byte[1024];

        // Length of the file:
        int length;

        // Total bytes to read:
        long dataToRead;

        // Identify the file to download including its path.
        string filepath = Server.MapPath(getPath);

        // Identify the file name.
        string filename = System.IO.Path.GetFileName(filepath);
        try
        {
            // Open the file.
            iStream = new System.IO.FileStream(filepath, System.IO.FileMode.Open,
            System.IO.FileAccess.Read, System.IO.FileShare.Read);


            // Total bytes to read:
            dataToRead = iStream.Length;
            Response.ContentType = "application/vnd.android.package-archive";
            Response.AddHeader("Content-Disposition", "attachment; filename=" + filename);

            // Read the bytes.
            while (dataToRead > 0)
            {
                // Verify that the client is connected.
                if (Response.IsClientConnected)
                {
                    // Read the data in buffer.
                    length = iStream.Read(buffer, 0, 1024);

                    // Write the data to the current output stream.
                    Response.OutputStream.Write(buffer, 0, length);

                    // Flush the data to the HTML output.
                    Response.Flush();

                    buffer = new Byte[1024];
                    dataToRead = dataToRead - length;
                }
                else
                {
                    //prevent infinite loop if user disconnects
                    dataToRead = -1;
                }
            }
        }
        catch (Exception ex)
        {
            // Trap the error, if any.
            Response.Write("Error : " + ex.Message);
        }
        finally
        {
            if (iStream != null)
            {
                //Close the file.
                iStream.Close();
            }
            Response.Close();
        }
    }


}

這是我的服務器端代碼，我正在嘗試使我的android .apk文件在鏈接單擊時可下載。 但是下載的文件是16 kb，即小於實際文件。 3.5 MB可能是什么樣的問題。 甚至我的手機內存也足以保存應用程序

Answer 1

您正在使用：

  Response.Flush();

在讀取流的循環中。 因此，您正在寫入Response.OutputStream，並在下一行中清除響應。

嘗試將整個流讀取為byte []，並且不要在循環中分配任何內容。

當byte []完成時，然后將內容分配給響應。

Answer 2

在IIS中，我為.apk定義了MIME類型“ application / vnd.android.package-archive”，並在aspx頁面中放置了超鏈接。

Answer 3

您確定您的客戶端（Android）代碼運行正常嗎？

這是我在客戶端測試過的解決方案：

private void downloadFile(String url, File outputFile) {
    try {

        URL u = new URL(url);
        URLConnection conn = u.openConnection();
        conn.connect();

        int contentLength = conn.getContentLength();

        // input stream to read file with 8k buffer
        InputStream input = new BufferedInputStream(u.openStream(), 8192);

        // output stream to write file
        OutputStream output = new  FileOutputStream(outputFile);

        publishDownloadProgress(0);
        toggleDownloadProgressbar(true);

        byte[] buffer = new byte[1024];
        long total= 0;
        int count;
        while((count = input.read(buffer)) != -1) {
            total += count;

            publishDownloadProgress((int) ((total*100) / contentLength));
            output.write(buffer, 0, count);
        }
        output.flush();
        output.close();
        input.close();

    } catch (FileNotFoundException e) {
        if(IsDebugging)
            Log.e("FileNotFoundException", e + "");
        return;
    } catch (IOException e) {
        if(IsDebugging)
            Log.e("IOException", e + "");
        return;
    }
}