[英]Laravel Eloquent ORM many-to-many Search Query
我正在使用Laravel v3,Eloquent和該應用程序的MySQL數據庫
我有一個員工數據庫,其中有一個搜索表單,其中顯示了符合搜索條件的員工列表。 您可以填寫一個或多個字段,它將僅與所有填寫的字段匹配。 如下所示: http : //i.stack.imgur.com/Ttfhr.png
搜索所有功能正常,除了我剛剛為“培訓”添加了多選。 員工可以附加零到許多培訓證書。 如果用戶要搜索名字“ Matt”,並在培訓搜索條件下選中“ CSTS”,則該列表將顯示所有具有與Matt相似的名字的員工,並且也接受過CSTS培訓。
數據庫架構如下:
user
--id
--first_name
--last_name
--job_title_id
etc...
training
--id
--name
--issused_date
--expiry_date
user_training
--id
--user_id
--training_id
用戶模型和培訓模型如下:
class User extends Eloquent {
public static $table = 'user';
public function training(){
return $this->has_many_and_belongs_to('training','user_training');
}
class Training extends Eloquent {
public static $table = 'training';
public function users(){
return $this->has_many_and_belongs_to('user','user_training');
}
}
我有以下代碼用於函數搜索,以及我嘗試進行的培訓:
Route::post('(:bundle)/list', function() {
$search = new StdClass();
$search->first_name = Input::get('first_name');
$search->last_name = Input::get('last_name');
$search->job_titles = Input::get('job_titles'); // array of ids/returns null if none selected
$search->training = Input::get('training'); // array of ids/returns null if none selected
$search->city = Input::get('city');
$search->province = Input::get('province');
$search->phone = Input::get('phone');
$search->status = Input::get('status');
$search->gender = Input::get('gender');
$search->hire_from_date = Input::get('hire_from_date');
$search->hire_to_date = Input::get('hire_to_date');
$search->current_location = Input::get('current_location');
$search->role = Input::get('role');
Session::put('search', $search); // so we can access inside query builder sub-functions
$query = User::where('active', '=', true);
if(!empty($search->training)) { // one or many
$query = User::with(array('training' => function($query) {
$s_search = Session::get('search');
//$query->where_in('training.id', $s_search->training);
//foreach($s_search->training as $id) {
// $query->where('training.id', '=', $id);
//}
}));
}
//$query = User::join('user_training', 'user.id', '=', 'user_training.user_id');
//$query->join('user_training', 'user.id', '=', 'user_training.user_id');
//$query->join('training', 'training.id', '=', 'user_training.training_id');
if(!empty($search->first_name)) { $query->where('first_name', 'LIKE', '%' . $search->first_name . '%'); }
if(!empty($search->last_name)) { $query->where('last_name', 'LIKE', '%' . $search->last_name . '%'); }
if(!empty($search->city)) { $query->where('city', 'LIKE', '%' . $search->city . '%'); }
if(!empty($search->province)) { $query->where('province_id', '=', $search->province); }
if(!empty($search->gender)) { $query->where('gender', '=', $search->gender); }
if(!empty($search->phone)) { $query->where('phone_1', 'LIKE', '%' . $search->phone . '%'); }
if(!empty($search->status)) { $query->where('status_id', '=', $search->status); }
if(!empty($search->role)) { $query->where('role_id', '=', $search->role); }
if(!empty($search->current_location)) { $query->where('location_id', '=', $search->current_location); }
if(!empty($search->hire_from_date)) // "after"
$query->where('hire_date', '>=', date('Y-m-d', strtotime($search->hire_from_date)));
if(!empty($search->hire_to_date)) // "before"
$query->where('hire_date', '<=', date('Y-m-d', strtotime($search->hire_to_date)));
if(!empty($search->job_titles)) { // one or many
$query->where(function($query){
$s_search = Session::get('search');
foreach($s_search->job_titles as $id) {
$query->or_where('job_title_id', '=', $id);
}
});
}
$query->order_by('last_name');
$user_list = $query->distinct()->get();
$user_count = $query->count();
var_dump($user_list); die;
if(Input::get('action') == 'export') {
if(Permission::check("Export Users CSV")) {
$now = new DateTime();
return Response::download(User::get_group_csv($user_list), date_format(new DateTime(), 'Y-m-d') . '_User_Export.csv');
}
}
“ $ user-> training”以簡單的id數組形式出現,它與Training-> id表匹配
多重選擇可以正確執行“職務標題”搜索,但是job_title_id在User表中,而不是關系中。
我試過循環,手動加入,使用急切的加載,使用Eloquent的“ with”,但都沒有成功。 有人可以指出我正確的方向嗎?
首先,您無需使用會話即可將變量獲取到匿名函數中。 嘗試改用“用途”。
// $search already defined
$query = User::where('active', '=', true);
if(!empty($search->training)) { // one or many
$query = User::with(array('training' => function($query) uses ($search) {
// Now you can use $search in this context
}));
}
}
另外,您在關系中使用小寫字符串,但是模型/類實際上是大寫的,因此它們應該像這樣:
class User extends Eloquent {
public static $table = 'user';
public function training(){
return $this->has_many_and_belongs_to('Training', 'user_training');
}
}
class Training extends Eloquent {
public static $table = 'training';
public function users(){
return $this->has_many_and_belongs_to('User', 'user_training');
}
}
第三,您聲明“ $ query = User :: where('active','=',true);” 然后覆蓋它。 也許您正在尋找:
if (!empty($search->training)) { // one or many
$query = User::with(array('training' => function($query) uses ($search) {
// Now you can use $search in this context
$query->where_in('training.id', $search->training);
}));
} else {
$query = User::with(array());
}
$query = $query->where('active', '=', true);
我可以提供更多的見解,但您的最終目標不是100%。
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