來自根目錄的PHP警告

Question

我的php代碼有問題。

文件夾名稱 what-c​​ounter此文件夾包含一個文件，其中包含以下名為counter.php的php代碼以及hitcount.txt文件。

<?php

$filename = '../what-counter/hitcount.txt';
$handle = fopen($filename, 'r');
$hits = trim(fgets($handle)) + 1;
fclose($handle);

$handle = fopen($filename, 'w');
fwrite($handle, $hits);
fclose($handle);

// Uncomment the next line (remove //) to display the number of hits on your page.
echo $hits;

?>

以下php代碼用於根目錄文件中，也用於回顯命中的文件夾中的文件中。

<?php include("../what-counter/counter.php"); ?>

問題代碼在文件夾中的文件中起作用，但在直接位於根目錄中的文件中則無效。 示例：index.php在根目錄中

使用此代碼我得到此警告

<?php include("what-counter/counter.php"); ?>

Warning: fopen(../what-counter/hitcount.txt) [function.fopen]: failed to open stream: No such file or directory in /home/what/public_html/what-counter/counter.php on line 4

Warning: fgets(): supplied argument is not a valid stream resource in /home/what/public_html/what-counter/counter.php on line 5

Warning: fclose(): supplied argument is not a valid stream resource in /home/what/public_html/what-counter/counter.php on line 6

Warning: fopen(../what-counter/hitcount.txt) [function.fopen]: failed to open stream: No such file or directory in /home/what/public_html/what-counter/counter.php on line 8

Warning: fwrite(): supplied argument is not a valid stream resource in /home/what/public_html/what-counter/counter.php on line 9

Warning: fclose(): supplied argument is not a valid stream resource in /home/what/public_html/what-counter/counter.php on line 10

並使用此代碼我得到此警告

<?php include("../what-counter/counter.php"); ?>

Warning: include(../what-counter/counter.php) [function.include]: failed to open stream: No such file or directory in /home/what/public_html/include/footer.php on line 31

Warning: include(../what-counter/counter.php) [function.include]: failed to open stream: No such file or directory in /home/what/public_html/include/footer.php on line 31

Warning: include() [function.include]: Failed opening '../what-counter/counter.php' for inclusion (include_path='.:/usr/lib/php:/usr/local/lib/php') in /home/what/public_html
/include/footer.php on line 31

我可以對$ filename url和<?php include("../what-counter/counter.php"); ?> <?php include("../what-counter/counter.php"); ?>得到它在文件中工作，根目錄以及文件夾？

Answer 1

要么：

• 包括相對文件： __DIR__.'/../somefile'; / __DIR__.'/somepath/somefile';
• 相對於已知目錄的包含：通常使用$_SERVER['DOCUMENT_ROOT'] ，以及引導程序代碼中類似於PROJECT_DIR的define() 。
• 將工作目錄更改為已知/靜態目錄chdir('/some/dir'); 。 不建議使用此代碼，因為調用代碼可能不會這樣。

Answer 2

聽起來像是絕對文件還是相對文件問題...

嘗試更換：

$filename = '../what-counter/hitcount.txt';

使用以下方法之一，取決於文件的確切位置：

$filename = __DIR__ . '/what-counter/hitcount.txt';
$filename = dirname(__DIR__) . '/what-counter/hitcount.txt';

或者（如果您使用的是舊版php）：

$filename = dirname(__FILE__) . '/what-counter/hitcount.txt';
$filename = dirname(dirname(__FILE__)) . '/what-counter/hitcount.txt';