[英]Error: JSON.parse: unexpected character at line 2 column 1 of the JSON data
[英]How can I fix JSON.parse: unexpected character Line 550 jQuery.js error for jTable plugin?
嗨,我正在使用php連接到我的數據庫。 這是我的列表操作代碼:表和數據庫確實具有相同的名稱
<?php
try
{
//Open database connection
$con = mysql_connect("localhost","root","");
mysql_select_db("702data", $con);
//Getting records (listAction)
if($_GET["action"] == "list")
{
//Get records from database
$result = mysql_query("SELECT * FROM 702data;");
//Add all records to an array
$rows = array();
while($row = mysql_fetch_assoc($result))
{
$rows[] = $row;
}
//Return result to jTable
$jTableResult = array();
$jTableResult['Result'] = "OK";
$jTableResult['Records'] = $rows;
print json_encode($jTableResult);
}
這是我的jtable初始化:
<body>
<div id="DeviceTableContainer"></div>
<script type="text/javascript">
$(document).ready(function() {
$('#DeviceTableContainer').jtable({
title: 'Wireless Monitor',
actions: {
listAction: 'DeviceActions.php?action=list',
createAction: 'DeviceActions.php?action=create',
updateAction: 'DeviceActions.php?action=update',
deleteAction: 'DeviceActions.php?action=delete'
},
fields: {
DeviceId: {
key: true,
list: false
},
DeviceTag: {
title: 'Device Tag',
width: '40%'
},
PV: {
title: 'PV',
width: '10%'
},
SV: {
title: 'SV',
width: '10%'
},
Timestamp: {
title: 'Timestamp',
width: '30%',
type: 'date',
create: false,
edit: false
}
}
});
$('#DeviceTableContainer').jtable('load');
});
</script>
</body>
我收到的錯誤是在jQuery.js的這一行上:
parseJSON: function( data ) {
// Attempt to parse using the native JSON parser first
if ( window.JSON && window.JSON.parse ) {
return window.JSON.parse( data );////////////////////////////////////
}
看起來它正在解析整個deviceactions.php文件,因為在Firebug中,數據對象將整個文件網絡作為字符串存儲到了網絡中。 我是Web開發人員的新手,因此可能很明顯。 如果重要的話,我也正在將其開發為Java Web應用程序。 謝謝
編輯:這是有關該錯誤的更多信息
parseJSON()jquery.js (line 550)
data = "<?php\r\ntry\r\n{\r\n //Open ...TableResult);\r\n}\r\n \r\n?>"
ajaxConvert()jquery.js (line 8447)
s = Object { url="DeviceActions.php?action=list", type="POST", isLocal=false, more...}
response = "<?php\r\ntry\r\n{\r\n //Open ...TableResult);\r\n}\r\n \r\n?>"
jqXHR = Object { readyState=4, responseText="<?php\r\ntry\r\n{\r\n //Open ...TableResult);\r\n}\r\n \r\n?>", getResponseHeader=function(), more...}
isSuccess = true
返回響應時,確保服務器(PHP)將內容類型標記為JSON
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