從iOS SDK中的日期獲取日期

Question

在我的應用程序中，要從日期中獲取日期（即Sunday ， Monday等）。

我的代碼如下：

NSDate *currentDate = [NSDate date];
    NSCalendar *calendar = [NSCalendar currentCalendar];

    //ask for current week
    NSDateComponents *comps = [[NSDateComponents alloc] init];
    comps=[calendar components:NSWeekCalendarUnit|NSYearCalendarUnit fromDate:currentDate];
    //create date on week start
    NSDate* weekstart=[calendar dateFromComponents:comps];

    //add 7 days
    NSMutableArray* week=[NSMutableArray arrayWithCapacity:7];
    for (int i=1; i<=7; i++) {
        NSDateComponents *compsToAdd = [[NSDateComponents alloc] init];
        compsToAdd.day=i;
        NSDate *nextDate = [calendar dateByAddingComponents:compsToAdd toDate:weekstart options:0];
        NSLog(@"%@",nextDate);  // date is 2013-06-30 18:30:00 +0000



        NSDateFormatter *myFormatter = [[NSDateFormatter alloc] init];
        [myFormatter setDateFormat:@"EEEE"]; // day, like "Saturday"
        //[myFormatter setDateFormat:@"c"]; // day number, like 7 for saturday

        NSString *dayOfWeek = [myFormatter stringFromDate:nextDate];

問題

        NSLog(@"Today is: %@", dayOfWeek);  // Prints Mondays instead of Sunday
    }

我該如何解決？

Answer 1

嘗試這個 ：

    NSCalendar* calender = [NSCalendar currentCalendar];
    NSDateComponents* component = [calender components:NSWeekdayCalendarUnit fromDate:[NSDate date]];
    return [component weekday]; // 1 for Sunday, 2 for Monday, and so on...

還可以從NSDate看到這一天的名字嗎？ 而這個https://discussions.apple.com/thread/1700102?start=0&tstart=0

編輯

嘗試這個

NSString * time = @"2013-06-30T11:00:26+0100";

NSDateFormatter *df = [[[NSDateFormatter alloc] init] autorelease];
[df setDateFormat:@"yyyy-MM-dd'T'HH:mm:ssZ"];
NSDate *date1 = [df dateFromString:time];
long lgTime = (long)[date1 timeIntervalSince1970];
NSLog(@"%ld", lgTime);


NSCalendar* calender = [NSCalendar currentCalendar];
NSDateComponents* component = [calender components:NSWeekdayCalendarUnit fromDate:date1];

NSLog(@"date=%@ === %@",[NSDate date],date1);
NSLog(@"day= %d",[component weekday]); ///it return 1

Answer 2

 NSCalendar* calender = [NSCalendar currentCalendar];

 NSDateComponents* component = [calender components:NSWeekdayCalendarUnit fromDate:[NSDate date]];

int weekDay = [component weekday];

NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
NSString *weekdayString = [[formatter weekdaySymbols] objectAtIndex:weekDay - 1];

NSLog(@"Day ::: %@", weekdayString);

Answer 3

NSDateFormatter* theDateFormatter = [[NSDateFormatter alloc] init];
[theDateFormatter setFormatterBehavior:NSDateFormatterBehavior10_4];
[theDateFormatter setDateFormat:@"EEEE"];
NSString *weekDay =  [theDateFormatter stringFromDate:[NSDate date]];

Answer 4

我做了一個小的NSDate類別，可以幫助您從日期中查找工作日名稱。 它返回工作日名稱的本地化字符串。 看看它。 您可以根據需要使用它。

NKLocalizedWeekday + NSDate

基本上，這是您需要的代碼：

NSCalendar *calendar = [NSCalendar currentCalendar];
NSDateComponents *components = [calendar components:NSWeekdayCalendarUnit fromDate:[NSDate date]];
int weekdayNumber = [components weekday];
NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
NSString *weekdayString = [[formatter weekdaySymbols] objectAtIndex:weekdayNumber - 1];

Answer 5

mydate = [NSDate date];
NSDateFormatter *dt2 = [ [NSDateFormatter alloc] init];
[dt2 setDateFormat:@"EEEE"];

NSString *day = [[NSString alloc] initWithFormat:@"%@",[dt2 stringFromDate:mydate]];

Answer 6

您遇到問題，因為它需要本地時區

嘗試這個

  NSDateFormatter *dateformate = [[NSDateFormatter alloc] init] ;
 [dateformate setTimeZone:[NSTimeZone timeZoneWithName:@"Australia/Sydney"]];
 [dateformate setDateFormat:@"EEEE"];
  NSLog(@"%@", [dateformate stringFromDate:[NSDate date]]);
  NSLog(@"%@", [NSTimeZone knownTimeZoneNames]);

設置所需的時區。它可能會起作用並為您提供幫助。

NSCalendar每周第一天鏈接中的類似問題請參考它。

Answer 7

我正在使用它，它在iOS 8.4中對我有用

-(NSString *) extractDayFromDate {
     NSCalendar* calender = [NSCalendar currentCalendar];
     NSDateComponents* component = [calender components:NSCalendarUnitWeekday fromDate:[NSDate date]];
     return [[calender weekdaySymbols] objectAtIndex:([component weekday]-1)]; 
}