[英]Cassandra keyspace in Titan graph data base
我使用Cassandra作為后端,並使用以下屬性在gremlin中創建了關鍵空間
conf=new BaseConfiguration();
conf.setProperty('storage.backend','cassandra');
conf.setProperty('storage.hostname','127.0.0.1');
conf.setProperty('storage.keyspace','MyTitanKeySpace');
g=TitanFactory.open(conf); //opening graph with configuration
Now I'm adding vertices namely subbu and sures and one relation between them
gremlin> Subbu=g.addVertex(null);// adding vertex name Subbu
==>v[4]
gremlin> Sures=g.addVertex(null);
==>v[8]
gremlin> Subbu.setProperty("name","subbu"); //assigning name Subbu to the vertex
==>null
gremlin> Sures.setProperty("name","sures");
==>null
gremlin> edge=g.addEdge(null,Subbu,Sures,'friends');//creating edge
==>e[x-8-2F0LaTPQAS][4-friends->8]
gremlin>g.commit();//save graph
gremlin>g.V
v[4]
v[8]
Now I'm creating one more graph with same key space name
f==TitanFactory.open(conf);
現在,我要添加頂點,即Muthu和Saran,以及它們之間的一種關系
gremlin> Muthu=f.addVertex(null); // adding vertex name Subbu
==>v[12]
gremlin> Saran=f.addVertex(null);
==>v[16]
gremlin> Muthu.setProperty("name","Muthu");//setting name to the vertex
==>null
gremlin> Saran.setProperty("name","Saran");
==>null
gremlin> edge=g.addEdge(null,Muthu,Saran,'friends');//creating edge
==>e[x-12-2F0LaTPQAS][12-friends->16]
gremlin>f.commit();//save graph
gremlin>f.V //displaying all vertices in graph f
v[4]
v[8]
v[12]
v[16]
It is showing all vertices in the key space but i want only particular graph vertices how it is possible why it is showing all vertices ?
有人可以回復我嗎?
也許您對TitanFactory.open
在做什么感到困惑。 你寫:
Now I'm creating one more graph with same key space name
f==TitanFactory.open(conf);
您不會使用該代碼“再創建一個圖”,而是在與該方法的第一次調用相同的鍵空間中連接到同一Cassandra實例。 它是同一張圖,因此當您使用gV
查看所有頂點時,您將看到在第一個連接中添加的頂點和在第二個連接中添加的頂點。
如果要共享一個Cassandra實例,則需要在調用TitanFactory.open(conf)
之前將conf
的鍵空間設置更改為其他鍵空間,在這種情況下,圖形應分開。
I did like this it is working fine
gremlin> g = TitanFactory.open(conf)
gremlin> pg = new PartitionGraph(g, '_partition', 'a')
==>partitiongraph[titangraph[inmemory:null]]
gremlin> Subbu = pg.addVertex(null)
==>v[4]
gremlin> Sures = pg.addVertex(null)
==>v[8]
etc...
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