C ++ Friend構造函數

Question

我有兩個類： Point ，它只存在於Space

class Point
{
private:
    Point(const Space &space, int x=0, int y=0, int z=0);
    int x, y, z;
    const Space & m_space;
};

構造函數是故意私有的，我不希望它被直接調用。 我想用這種方式創建點數

Space mySpace;
Point myPoint = mySpace.Point(5,7,3);

有沒有辦法這樣做？ 謝謝。

Answer 1

是的，將Space::Point()聲明為友元方法。 該方法將獲得Point的私人成員的訪問權限。

class Point
{
public:
    friend Point Space::Point(int, int, int);
private:
    // ...

Answer 2

我會這樣做：

class Space
{
public:
    class Point
    {
    private:
        Point(const Space &space, int x=0, int y=0, int z=0);
        int m_x, m_y, m_z;
        const Space & m_space;

    friend class Space;
    };

    Point MakePoint(int x=0, int y=0, int z=0);
};

Space::Point::Point(const Space &space, int x, int y, int z)
    : m_space(space), m_x(x), m_y(y), m_z(z)
{
}

Space::Point Space::MakePoint(int x, int y, int z)
{
    return Point(*this, x, y, z);
}

Space mySpace;
Space::Point myPoint = mySpace.MakePoint(5,7,3);