在Oracle中的一個SQL Select中包含2個listagg

Question

我有一張表格，形式為：

| ID    | COURSE | PASS |
---------------------------
| 1     | 1      | 1      |
| 1     | 2      | 1      |    
| 1     | 3      | 1      |
| 1     | 4      | 0      |
| 1     | 5      | 0      |

我想要表格形式的行：

| ID    | FAILED | PASSED |
---------------------------
| 1     | 4,5    | 1,2,3  |

我唯一想到的是這樣的：

    select NVL(passed.id, failed.id), passed.test, failed.test from 
        (select id, listagg(course, ',') within group (order by course) test from table1 where pass = 1 group by id ) passed 
    full outer join
        (select id, listagg(course, ',') within group (order by course) test from table1 where pass = 0 group by id ) failed
    on passed.id = failed.id

有沒有辦法在單個查詢中做到這一點？

Answer 1

嘗試

select  id, 
  listagg(case when pass = 1 then course end, ',') within group (order by course) passed,
  listagg(case when pass = 0 then course end, ',') within group (order by course) failed
from table1
group by id

這是一個sqlfiddle演示