[英]Jackson deserialization with unknown dynamic properties
我有一個JSON字符串,如:
"shipping_profiles": {
"563": {
"name": "name",
"value": "value"
},
"564": {
"name": "name",
"value": "value"
},
"565": {
"name": "name",
"value": "value"
},
"566": {
"name": "name",
"value": "value"
}
}
現在我用Jackson 2.0解析它。 我想從JSON字符串中獲取List<shipping_profiles>
。
可能嗎?
您的shipping_profiles
屬性看起來不像數組。 它表示具有動態屬性的對象,因此我們應該將其視為對象。 如果我們對屬性@JsonAnySetter
我們可以使用@JsonAnySetter
注釋。 算法可能如下所示:
請參閱我的示例實現。 我希望,它可以幫助您解決問題。 輸入JSON:
{
"shipping_profiles":{
"563":{
"name":"name563",
"value":"value563"
},
"564":{
"name":"name564",
"value":"value564"
},
"565":{
"name":"name565",
"value":"value565"
},
"566":{
"name":"name566",
"value":"value566"
}
}
}
示例程序:
import java.io.File;
import java.io.IOException;
import java.util.ArrayList;
import java.util.List;
import java.util.Map;
import com.fasterxml.jackson.annotation.JsonAnySetter;
import com.fasterxml.jackson.annotation.JsonProperty;
import com.fasterxml.jackson.databind.ObjectMapper;
public class JacksonProgram {
public static void main(String[] args) throws IOException {
ObjectMapper mapper = new ObjectMapper();
File source = new File("X:/test.json");
Entity entity = mapper.readValue(source, Entity.class);
ShippingProfiles shippingProfiles = entity.getShippingProfiles();
List<Map<String, String>> profileMaps = shippingProfiles.getProfiles();
List<Profile> profiles = new ArrayList<Profile>(profileMaps.size());
for (Map<String, String> item : profileMaps) {
profiles.add(mapper.convertValue(item, Profile.class));
}
System.out.println(profiles);
}
}
class Entity {
@JsonProperty("shipping_profiles")
private ShippingProfiles shippingProfiles;
public ShippingProfiles getShippingProfiles() {
return shippingProfiles;
}
public void setShippingProfiles(ShippingProfiles shippingProfiles) {
this.shippingProfiles = shippingProfiles;
}
}
class ShippingProfiles {
private List<Map<String, String>> profiles = new ArrayList<Map<String, String>>();
@JsonAnySetter
public void setDynamicProperty(String name, Map<String, String> map) {
profiles.add(map);
}
public List<Map<String, String>> getProfiles() {
return profiles;
}
public void setProfiles(List<Map<String, String>> profiles) {
this.profiles = profiles;
}
}
class Profile {
private String name;
private String value;
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getValue() {
return value;
}
public void setValue(String value) {
this.value = value;
}
@Override
public String toString() {
return "Profile [name=" + name + ", value=" + value + "]";
}
}
以上app打印:
[Profile [name=name563, value=value563], Profile [name=name564, value=value564], Profile [name=name565, value=value565], Profile [name=name566, value=value566]]
我使用@michalziober提供的方式解析了我的json動態屬性。
"commandClasses": {
"32": {
"name": "Basic",
"data": {
"name": "devices.1.instances.1.commandClasses.32.data",
"value": null,
"type": "NoneType"
},
"38": {
"name": "SwitchMultilevel",
"data": {
"name": "devices.1.instances.1.commandClasses.38.data",
"value": null,
"type": "NoneType"
},
"43": {
"name": "SceneActivation",
"data": {
"name": "devices.1.instances.1.commandClasses.43.data",
"value": null,
"type": "NoneType"
}
有了這個json,我還需要保存那個動態屬性,所以我添加了另一個List來存儲它。
public class CommandClasses {
private List<String> nameList = new ArrayList<String>();
private List<CommandClass> commmandClasses = new ArrayList<CommandClass>();
private Logger logger = Logger.getInstance(CommandClasses.class);
@JsonAnySetter
public void setDynamicCommandClass(String name, CommandClass cc) {
logger.d("@ adding new CC : " + name);
nameList.add(name);
commmandClasses.add(cc);
}
public List<CommandClass> getCommmandClasses() {
return commmandClasses;
}
public void setCommmandClasses(List<CommandClass> commmandClasses) {
this.commmandClasses = commmandClasses;
}
}
現在我也可以訪問該字段作為id以便稍后發送請求。
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