[英]DB Schema not generated: illegalargumentexception unknown entity on Play Framework 2.4 + JPA Hibernate + Heroku
[英]Hibernate/JPA : IllegalArgumentException: Not an entity
我嘗試使用 hibernate 和 jpa 運行一個基本的應用程序,但是現在我在運行應用程序時遇到了這個異常……這是下面的代碼和錯誤:
java.lang.IllegalArgumentException: Not an entity: class pka.EclipseJPAExample.domain.Employee
at org.hibernate.ejb.metamodel.MetamodelImpl.entity(MetamodelImpl.java:158)
at org.hibernate.ejb.criteria.QueryStructure.from(QueryStructure.java:136)
at org.hibernate.ejb.criteria.CriteriaQueryImpl.from(CriteriaQueryImpl.java:177)
at pka.EclipseJPAExample.jpa.JpaTest.createEmployees(JpaTest.java:47)
at pka.EclipseJPAExample.jpa.JpaTest.main(JpaTest.java:33)
JpaTest.java:
public class JpaTest {
private EntityManager manager;
public JpaTest(EntityManager manager) {
this.manager = manager;
}
/**
* @param args
*/
public static void main(String[] args) {
EntityManagerFactory factory = Persistence.createEntityManagerFactory("persistenceUnit");
EntityManager manager = factory.createEntityManager();
JpaTest test = new JpaTest(manager);
EntityTransaction tx = manager.getTransaction();
tx.begin();
try {
test.createEmployees();
} catch (Exception e) {
e.printStackTrace();
}
tx.commit();
test.listEmployees();
System.out.println(".. done");
}
private void createEmployees() {
CriteriaBuilder builder = manager.getCriteriaBuilder();
CriteriaQuery<Employee> query = builder.createQuery(Employee.class);
query.from(Employee.class);
int numOfEmployees = manager.createQuery(query).getResultList().size();
if (numOfEmployees == 0) {
Department department = new Department("java");
manager.persist(department);
manager.persist(new Employee("Jakab Gipsz",department));
manager.persist(new Employee("Captain Nemo",department));
}
}
private void listEmployees() {
CriteriaBuilder builder = manager.getCriteriaBuilder();
CriteriaQuery<Employee> query = builder.createQuery(Employee.class);
query.from(Employee.class);
List<Employee> resultList = manager.createQuery(query).getResultList();
for (Employee next : resultList) {
System.out.println("next employee: " + next);
}
}
}
和persistence.xml:
....<persistence-unit name="persistenceUnit" transaction-type="RESOURCE_LOCAL">
<exclude-unlisted-classes>false</exclude-unlisted-classes>
<properties>
<property name="javax.persistence.jdbc.driver" value="com.mysql.jdbc.Driver" />
<property name="javax.persistence.jdbc.url" value="jdbc:mysql://localhost:3306/testowa" />
<property name="javax.persistence.jdbc.user" value="root" />
<property name="javax.persistence.jdbc.password" value="enchantsql" />
<property name="hbm2ddl.auto" value="create" />
<property name="hibernate.dialect" value="org.hibernate.dialect.MySQLDialect" />
</properties>
</persistence-unit>....
你能指出問題出在哪里嗎?
編輯:我忘了粘貼 Employee 類...所以這里是下面:
@Entity
@Table(name="Employee")
public class Employee {
@Id
@GeneratedValue
private Long id;
private String name;
@ManyToOne
private Department department;
public Employee() {}
public Employee(String name, Department department) {
this.name = name;
this.department = department;
}
public Employee(String name) {
this.name = name;
}
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public Department getDepartment() {
return department;
}
public void setDepartment(Department department) {
this.department = department;
}
@Override
public String toString() {
return "Employee [id=" + id + ", name=" + name + ", department="
+ department.getName() + "]";
}
}
如您所見,它已被映射。
確保您的實體中有@Entity
注釋。 你還需要在persistence.xml
配置一個實體
<persistence-unit name="persistenceUnit" transaction-type="RESOURCE_LOCAL">
<class>pka.EclipseJPAExample.domain.Employee</class>
如果您的應用程序中有許多 ENTITY 類,那么在“persistence.xml”中為每個實體添加一個條目將不是一個好的選擇。
相反,使用自定義自動配置創建您自己的數據源 bean。
在 dataSource bean 創建方法中使用 LocalContainerEntityManagerFactoryBean。
在這里,您需要定義
LocalContainerEntityManagerFactoryBean entityManagerFactoryBean = new
LocalContainerEntityManagerFactoryBean();
entityManagerFactoryBean.setPackagesToScan("org.springframework.boot.entities");
這個包是保存所有實體類的位置。 因此無需在“persistence.xml”中定義實體類的每個條目。
首選基於 Spring 的掃描。
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