[英]Issues with Parameters
我一直在嘗試我的PHP技能,似乎當我嘗試將信息從我的Android應用程序發送到PHP時,似乎只發送了參數名稱(數據庫顯示:Lname作為示例。)數據庫。 我們正在使用PDO作為與MySQL數據庫通信的方式。
編碼如下:
$query = "INSERT INTO Customer ( Lname, Fname, Address, City, State, ZIP, Phone, myusername, mypassword ) VALUES ( ':Lname', ':Fname', ':Address', ':City', ':State', ':ZIP', ':Phone', ':myusername', ':mypassword')";
//Again, we need to update our tokens with the actual data:
$query_params = array(
':Lname' => $_POST['LName'],
':Fname' => $_POST['FName'],
':Address' => $_POST['Address'],
':City' => $_POST['City'],
':State' => $_POST['State'],
':ZIP' => $_POST['ZIP'],
':Phone' => $_POST['Phone'],
':myusername' => $_POST['username'],
':mypassword' => $_POST['password']
);
//time to run our query, and create the user
try {
$stmt = $db->prepare($query);
$result = $stmt->execute($query_params);
}
catch (PDOException $ex) {
// For testing, you could use a die and message.
//die("Failed to run query: " . $ex->getMessage());
//or just use this use this one:
$response["success"] = 0;
$response["message"] = $ex->getMessage();
die(json_encode($response));
}
您已經在查詢字符串中包括了文字值。
$query = "INSERT INTO Customer ( Lname, Fname, Address, City, State, ZIP, Phone, myusername, mypassword )
VALUES ( ':Lname', ':Fname', ':Address', ':City', ':State', ':ZIP', ':Phone', ':myusername', ':mypassword')";
應該
$query = "INSERT INTO Customer ( Lname, Fname, Address, City, State, ZIP, Phone, myusername, mypassword )
VALUES ( :Lname, :Fname, :Address, :City, :State, :ZIP, :Phone, :myusername, :mypassword)";
您需要從SQL值中刪除引號,因為它會被解釋為文字字符串。 如果刪除它們,則應該一切都很好:)
$query = "INSERT INTO Customer ( Lname, Fname, Address, City, State, ZIP, Phone, myusername, mypassword ) VALUES ( ':Lname', ':Fname', ':Address', ':City', ':State', ':ZIP', ':Phone', ':myusername', ':mypassword')";
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