[英]How to update multiple queries as one
這是mu查詢
$sql_query= "insert into shortdb1.currency_code set currency_code = 'KWD',
based_on = 'KWD', currency_rate = '1.00',
last_update = '2013-07-25 11:41:33';
insert into shortdb1.currency set currency_code = 'KWD',
language_code = 'EN', currency_name = 'Kuwaiti Dinar';";
$conn_1->query($sql_query)
但我得到錯誤
您的SQL語法有錯誤; 查看與MySQL服務器版本對應的手冊,以便在' insert into shortdb1.currency set currency_code = 'KWD', language_code = 'EN','
第4行附近使用正確的語法
您的查詢需要存儲為字符串,即:
$sql_query = insert into shortdb1.currency_code set currency_code = 'INR', based_on = 'KWD', currency_rate = '200', last_update = '2013-07-25 11:14:26';
需要是
$sql_query = "insert into shortdb1.currency_code set currency_code = 'INR', based_on = 'KWD', currency_rate = '200', last_update = '2013-07-25 11:14:26'";
查詢和php句子結尾處缺少大量的引號和分號:
$sql_query = "insert into shortdb1.currency_code set currency_code = 'INR', based_on = 'KWD', currency_rate = '200', last_update = '2013-07-25 11:14:26';";
$sql_query .= "insert into shortdb1.currency set currency_code = 'INR', language_code = 'EN', currency_name = 'Indian Rupee', based_on = 'KWD', currency_rate = '200', last_update = '2013-07-25 11:14:26';";
$conn_1->query($sql_query);
如果要發送多個更新查詢,可以使用事務
$firstQuery = "insert into shortdb1.currency_code set currency_code = 'KWD', based_on = 'KWD', currency_rate = '1.00', last_update = '2013-07-25 11:41:33'";
$secondQuery = "insert into shortdb1.currency set currency_code = 'KWD', language_code = 'EN', currency_name = 'Kuwaiti Dinar';";
try {
// create transaction
$conn->beginTransaction();
// multiple query commands
$conn->query($firstQuery);
$conn->query($secondQuery);
// ect...
// if we are here, then the above query got passed correctly without exception
// now we can commit the transaction
$conn->commit();
}
catch (Exception $e) {
// if above commands fails, the db gets a rollback task
$conn->rollback();
}
這是在一個序列中對數據庫使用多個插入/更新查詢的好方法。
事務的強大之處在於,您可以創建一個更新查詢數組,並在上面的塊中循環遍歷該數組,而不是多行查詢。
我認為您的查詢形成錯誤。 SET
關鍵字用於UPDATE
查詢。
對於INSERT
查詢,它應采用以下形式:
INSERT INTO TABLE_NAME (column1, column2, column3)
VALUES (value1, value2, value3);
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