單擊即可彈出多個對話框

Question

我有以下代碼來生成對話框。 流量像這樣

測試結束->用戶選擇保存或刪除->如果用戶選擇刪除，則會彈出另一個對話框，要求刪除確認。

該程序工作正常。 但是，有時會彈出1個以上的刪除對話框。 我在某處犯錯了嗎？

謝謝。

private void buildEndTestDialog(){

    alert = new AlertDialog.Builder(getActivity());
    alert.setTitle("End of Test");
    alert.setCancelable(false);


    alert.setNegativeButton("Save", new DialogInterface.OnClickListener() {
        public void onClick(DialogInterface dialog, int whichButton) {
            //Save
            alert.dismiss();
        }
    });

    alert.setPositiveButton("Delete", new DialogInterface.OnClickListener() {
        public void onClick(DialogInterface dialog, int whichButton) {
            buildDeleteDialog();
        }
    });

    alert.show(); 
}

private void buildDeleteDialog() {

    alert = new AlertDialog.Builder(getActivity());
    alert.setTitle("Delete");
    alert.setCancelable(false);
    alert.setMessage("Are you sure you want to delete this result?");
    alert.setNegativeButton("Yes", new DialogInterface.OnClickListener() {
        public void onClick(DialogInterface dialog, int whichButton) {
            //delete result
        }
    });

    alert.setPositiveButton("No", new DialogInterface.OnClickListener() {
        public void onClick(DialogInterface dialog, int whichButton) {

            dialog.dismiss();
        }
    });

    alert.show(); 
}

Answer 1

嘗試..

    private void buildEndTestDialog(){
               ///rest of code
        alert.setPositiveButton("Delete", new DialogInterface.OnClickListener() {
            public void onClick(DialogInterface dialog, int whichButton) {
                dialog.dismiss();
                buildDeleteDialog();
            }
        });

        alert.show(); 
    }

    private void buildDeleteDialog() {

        ///rest of code

        alert.setPositiveButton("No", new DialogInterface.OnClickListener() {
            public void onClick(DialogInterface dialog, int whichButton) {

                dialog.dismiss();
               buildEndTestDialog();
            }
        });

        alert.show(); 
    }