[英]Convert integer MAC address to string in Javascript
我有一個存儲為原始 48 位數字的 MAC 地址,我想將其拆分並以 xx:xx:xx:xx:xx:xx 的標准十六進制格式打印。 例如,原始數字 81952921372024 應該變成 78:45:c4:26:89:4a。 我的第一次嘗試是,
var suspect = {mac: 2333752735057272};
console.log(
Number(suspect.mac & 0xFF).toString(16) + ":" +
Number((suspect.mac & 0xFF00) >> 8).toString(16) + ":" +
Number((suspect.mac & 0xFF0000) >> 16).toString(16) + ":" +
Number((suspect.mac & 0xFF000000) >> 24).toString(16) + ":" +
Number((suspect.mac & 0xFF00000000) >> 32).toString(16) + ":" +
Number((suspect.mac & 0xFF0000000000) >> 48).toString(16));
但是因為 Javascript 在進行移位操作時顯然無法處理 > 32 位整數,所以最后兩個八位字節總是為 0,
78:45:c4:26:0:0
一個簡單的方法如下所示:
var mac = 81952921372024;
mac.toString( 16 ) // "4a8926c44578"
.match( /.{1,2}/g ) // ["4a", "89", "26", "c4", "45", "78"]
.reverse() // ["78", "45", "c4", "26", "89", "4a"]
.join( ':' ) // "78:45:c4:26:89:4a"
> "78:45:c4:26:89:4a"
但是,當您的整數非常短(即mac = 150
)時,我建議僅針對病理情況放置額外的00
組:
var mac = 81952921372024;
new Array( 6 ).join( '00' ) // '000000000000'
.match( /../g ) // [ '00', '00', '00', '00', '00', '00' ]
.concat(
mac.toString( 16 ) // "4a8926c44578"
.match( /.{1,2}/g ) // ["4a", "89", "26", "c4", "45", "78"]
) // ["00", "00", "00", "00", "00", "00", "4a", "89", "26", "c4", "45", "78"]
.reverse() // ["78", "45", "c4", "26", "89", "4a", "00", "00", "00", "00", "00", "00", ]
.slice( 0, 6 ) // ["78", "45", "c4", "26", "89", "4a" ]
.join( ':' ) // "78:45:c4:26:89:4a"
> "78:45:c4:26:89:4a"
以下工作,
var hexValue = parseInt('44873434449413').toString(16);
var macaddress = [];
for (var i=0; i < hexValue.length; i=i+2) {
macaddress.push(hexValue.substr(i,2));
}
console.log(macaddress.join(':'));
輸出:
28:cf:e9:1e:c6:05
編輯:
處理尾隨 0
str='3';
if (str.length < 12) { str = pad_after(str, 12, 0);}
var hexValue = parseInt(str).toString(16);
if (hexValue.length < 12) { hexValue = pad_before(hexValue, 12, 0);}
var macaddress = [];
for (var i=0; i < hexValue.length; i=i+2) {
macaddress.push(hexValue.substr(i,2));
}
console.log(macaddress.join(':'));
function pad_before(n, width, z) {
z = z || '0';
n = n + '';
return n.length >= width ? n : new Array(width - n.length + 1).join(z) + n;
}
function pad_after(n, width, z) {
z = z || '0';
n = n + '';
return n.length >= width ? n : n + new Array(width - n.length + 1).join(z);
}
輸出:
00:45:d9:64:b8:00
接受的答案沒有通過我的單元測試(將 mac 地址轉換為數字然后轉換回來並期望結果等於輸入)。
正如@blueren所說,接受的答案返回相反的結果。
我的版本是:
(mac_num).toString(16).padStart(12, '0').match(/../g)
.reverse()
.slice(0, 6)
.reverse()
.join(':')
我的測試:
expect(mac.toString(mac.toLong('b4:ae:2b:db:1c:3d'))).to.deep.equal('b4:ae:2b:db:1c:3d');
expect(mac.toString(mac.toLong('00:00:00:db:1c:3d'))).to.deep.equal('00:00:00:db:1c:3d');
expect(mac.toString(mac.toLong('b4:ae:2b:00:00:00'))).to.deep.equal('b4:ae:2b:00:00:00');
expect(mac.toString(mac.toLong('00:00:00:00:00:00'))).to.deep.equal('00:00:00:00:00:00');
expect(mac.toString(mac.toLong('10:00:00:00:00:00'))).to.deep.equal('10:00:00:00:00:00');
expect(mac.toString(mac.toLong('00:00:01:00:00:00'))).to.deep.equal('00:00:01:00:00:00');
expect(mac.toString(mac.toLong('00:00:00:00:00:01'))).to.deep.equal('00:00:00:00:00:01');
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