使用Boost QT和mingw的多線程

Question

我正在QT上使用C ++（librairie OpenCV）開發GUI，效果很好。 現在我正在嘗試使用boost多線程代碼，我的方法是：

//creating thread group
 thread_group mythread;
//then creating threads 

    mythread.create_thread(bind(&MainWindow::setbarvalue,this,0) ) ;

//set max and min of a progressbar to zero to get a floatting progressbar


 mythread.create_thread(bind(&AVI2Image::Convert_AVItoImage,&avitoim,Nom,firstframe, lastframe,Nom_save,digitsnumber)) ;

AVI2Image：該類

Convert_AVItoImage：函數

avitoim：類的實例

然后是屬性

這條線也可以。

問題開始於這一行：

 mythread.create_thread(bind(&Lecture_containerYUV::container_YUV2yuv,&lectcont, Nom,Nom_save, width ,height,Redimonsionne,width_desir,height_desir, filter,inputsampling,
                             inputbitdepth,nbimages,digitsnumber,ry6,ru6,rv6,gy6,gu6,gv6,by6,bu6,bv6,coeff1,coeff2,coeff3,contrast,gamma,ry7,ru7,rv7,gy7,gu7,gv7,by7,bu7
                             ,bv7,ry2,ru2,rv2,gy2,gu2,gv2,by2,bu2,bv2));

其方法與上述相同，但在此出現此錯誤：

C:\Users\Mido\Documents\Container_ConverterV_2.4\mainwindow.cpp:363: erreur : no matching function for call to 'bind(void (Lecture_containerYUV::*)(std::string, std::string, int, int, bool, int, int, int, int, int, int, int, double, double, double, double, double, double, double, double, double, double, double, double, double, double, double, double, double, double, double, double, double, double, double, double, double, double, double, double, double, double, double, double), Lecture_containerYUV*, std::string&, std::string&, int&, int&, bool&, int&, int&, int&, int&, int&, int&, int&, double&, double&, double&, double&, double&, double&, double&, double&, double&, double&, double&, double&, double&, double&, double&, double&, double&, double&, double&, double&, double&, double&, double&, double&, double&, double&, double&, double&, double&, double&, double&, double&)'

和：

lectcont.container_YUV2yuv( Nom,Nom_save, width ,height,Redimonsionne,width_desir,height_desir, filter,inputsampling,
                             inputbitdepth,nbimages,digitsnumber,ry6,ru6,rv6,gy6,gu6,gv6,by6,bu6,bv6,coeff1,coeff2,coeff3,contrast,gamma,ry7,ru7,rv7,gy7,gu7,gv7,by7,bu7
                             ,bv7,ry2,ru2,rv2,gy2,gu2,gv2,by2,bu2,bv2);

工作正常！！！

mingw找不到我不明白為什么的功能！

任何幫助請

Answer 1

我認為問題是您無法輸入匹配參數。 我建議您使用C ++ 11的多線程

MyThread.h

#ifndef MyTHREAD_HPP
#define MyTHREAD_HPP

#include <thread>
#include <mutex>

class MyThread {


public:
    MyThread();
    void PrintOutMessage(string msg);
    void PrintOut(int i, int j, int k);
    void PrintOut(int i, int j);
    ~MyThread();
};
#endif

MyThread.cpp

#include "MyThread.hpp"


mutex _mu, _mu2;

MyThread::MyThread()
{

}


MyThread::~MyThread()
{
}

void MyThread::PrintOutMessage(string msg)
{

    for (int l = 0; l < 10; l++)
    {

        lock(_mu, _mu2);
        lock_guard<mutex>locker(_mu2, adopt_lock);
        lock_guard<mutex>locker2(_mu, adopt_lock);

        cout<< "message:" << msg << endl;
        Sleep(200);
    }

}

void MyThread::PrintOut(int i,int j,int k)
{


    for (int l = 0; l < 10; l++)
    {
        lock(_mu, _mu2);
        //lock_guard<mutex>locker(_mu2, adopt_lock);
        //lock_guard<mutex>locker2(_mu, adopt_lock);
        unique_lock<mutex>locker(_mu2, adopt_lock);
        unique_lock<mutex>locker2(_mu, adopt_lock);
        cout << "message:" << i << ", " << j << ", " << k << endl;
        Sleep(200);
    }

}

void MyThread::PrintOut(int i, int j)
{


    for (int l = 0; l < 10; l++)
    {
        lock(_mu, _mu2);
        lock_guard<mutex>locker(_mu2, adopt_lock);
        lock_guard<mutex>locker2(_mu, adopt_lock);

        cout << "message:" << i << ", " << j << endl;
        Sleep(200);
    }

}

main.cpp

#include "MyThread.hpp"

void (MyThread::*memfunc)(int,int) = &MyThread::PrintOut;
void (MyThread::*memfunc2)(int, int,int) = &MyThread::PrintOut;

void PrintOutmainfunc(int i, int j, int k)
{


    for (int l = 0; l < 10; l++)
    {

        cout << "message:" << i << ", " << j << ", " << k << endl;
        Sleep(200);
    }

}
int main (){

    string msg = " hello world";
    int i = 10, j = 20, k = 30;
    //  string str = lexical_cast<string>(i);
    //cout << "str: " << str << endl;

    MyThread mythread;

    thread t1(memfunc, mythread, i, j);
    thread t2(memfunc2, mythread, i, j, k);
    thread t3(&MyThread::PrintOutMessage, mythread, msg);
    //thread t4(PrintOutmainfunc, i, j, k);

    //thread t3(bind(&MyThread::PrintOutMessage, mythread, msg));

    t1.join();
    t2.join();
    t3.join();
    //t4.join();

    system("PAUSE");
    return 0;
}

在此示例中，我將多線程的所有可能選項