按日期范圍分組在t-sql中

Question

我正在嘗試對此表進行查詢：

Id       startdate     enddate       amount
1        2013-01-01   2013-01-31      0.00
2        2013-02-01   2013-02-28      0.00
3        2013-03-01   2013-03-31      245
4        2013-04-01   2013-04-30      529
5        2013-05-01   2013-05-31      0.00
6        2013-06-01   2013-06-30      383
7        2013-07-01   2013-07-31      0.00
8        2013-08-01   2013-08-31      0.00

我想獲得輸出：

2013-01-01          2013-02-28          0
2013-03-01          2013-06-30          1157
2013-07-01          2013-08-31           0

我想得到這個結果，所以我會知道什么時候開始進貨，什么時候停止。 我也對錢開始進入之前的幾個月（第一行解釋）以及資金停止的月數感興趣（這也解釋了為什么我對2013年7月到2013年8月的第3行感興趣）。

我知道我可以在日期上使用最小值和最大值並總結金額，但我無法弄清楚如何將記錄划分為這種方式。
謝謝！

Answer 1

with CT as
(
    select t1.*,
           ( select max(endDate) 
             from t 
             where startDate<t1.StartDate and SIGN(amount)<>SIGN(t1.Amount)
           ) as GroupDate
    from t  as t1
) 
select min(StartDate) as StartDate,
       max(EndDate) as EndDate,
       sum(Amount) as Amount
from CT
group by GroupDate
order by StartDate

SQLFiddle演示

Answer 2

這是一個想法（也是一個小提琴 ）：

;WITH MoneyComingIn AS
(
    SELECT MIN(startdate) AS startdate, MAX(enddate) AS enddate, 
        SUM(amount) AS amount
    FROM myTable
    WHERE amount > 0
)
SELECT MIN(startdate) AS startdate, MAX(enddate) AS enddate, 
    SUM(amount) AS amount
FROM myTable
WHERE enddate < (SELECT startdate FROM MoneyComingIn)
UNION ALL
SELECT startdate, enddate, amount
FROM MoneyComingIn
UNION ALL
SELECT MIN(startdate) AS startdate, MAX(enddate) AS enddate, 
    SUM(amount) AS amount
FROM myTable
WHERE startdate > (SELECT enddate FROM MoneyComingIn)

---

第二，不使用UNION （ 小提琴 ）：

SELECT MIN(startdate), MAX(enddate), SUM(amount)
FROM
(
    SELECT startdate, enddate, amount,
    CASE 
        WHEN EXISTS(SELECT 1 
                    FROM myTable b 
                    WHERE b.id>=a.id AND b.amount > 0) THEN
            CASE WHEN EXISTS(SELECT 1 
                             FROM myTable b 
                             WHERE b.id<=a.id AND b.amount > 0) 
                 THEN 2 
                 ELSE 1 
            END
        ELSE 3
    END AS partition_no
    FROM myTable a
) x
GROUP BY partition_no

雖然我認為正如所寫，它假定Id是有序的。 您可以使用ROW_NUMBER() OVER(ORDER BY startdate)替換它。

Answer 3

這樣的事情應該這樣做：

select min(startdate), max(enddate), sum(amount) from paiements
   where enddate   < (select min(startdate) from paiements where amount >0)
union
select min(startdate), max(enddate), sum(amount) from paiements
   where startdate >= (select min(startdate) from paiements where amount >0)
     and enddate   <= (select max(enddate) from paiements where amount >0)
union
select min(startdate), max(enddate), sum(amount) from paiements
   where startdate > (select max(enddate) from paiements where amount >0)

但對於這種報告，使用多個查詢可能更明確。

Answer 4

這樣做你想要的：

-- determine the three periods
DECLARE @StartMoneyIn INT
DECLARE @EndMoneyIn INT

SELECT @StartMoneyIn = MIN(Id)
FROM [Amounts]
WHERE amount > 0

SELECT @EndMoneyIn = MAX(Id)
FROM [Amounts]
WHERE amount > 0

-- retrieve the amounts
SELECT MIN(startdate) AS startdate, MAX(enddate) AS enddate, SUM(amount) AS amount
FROM [Amounts]
WHERE Id < @StartMoneyIn
UNION
SELECT MIN(startdate), MAX(enddate), SUM(amount)
FROM [Amounts]
WHERE Id >= @StartMoneyIn AND Id <= @EndMoneyIn
UNION
SELECT MIN(startdate), MAX(enddate), SUM(amount)
FROM [Amounts]
WHERE Id > @EndMoneyIn

Answer 5

如果你想做的就是看錢什么時候開始進來以及什么時候停止，這可能對你有用：

select 
    min(startdate),
    max(enddate),
    sum(amount)
where
    amount > 0

這不包括沒有錢進入的時期。

Answer 6

如果您不關心期間的總數，但只想要從0到某事的記錄，反之亦然，您可以做一些像這樣的瘋狂事情：

select *
from MoneyTable mt
where exists ( select *
               from MoneyTable mtTemp
               where mtTemp.enddate = dateadd(day, -1, mt.startDate)
               and mtTemp.amount <> mt.amount
               and mtTemp.amount * mt.amount = 0)

或者，如果您必須包含第一條記錄：

select *
from MoneyTable mt
where exists ( select *
               from MoneyTable mtTemp
               where mtTemp.enddate = dateadd(day, -1, mt.startDate)
               and mtTemp.amount <> mt.amount
               and mtTemp.amount * mt.amount = 0 )
or not exists ( select *
                from MoneyTable mtTemp
                where mtTemp.enddate = dateadd(day, -1, mt.startDate))

Sql小提琴