遍歷mysqli結果

Question

我正在嘗試顯示登錄用戶正在關注的藝術家的狀態更新列表。

到目前為止，我有這個：

#Get the list of artists that the user has liked
$q = "SELECT * FROM artist_likes WHERE user_id = '1' ";
$r = mysqli_query($dbc,$q);
while ($row = mysqli_fetch_array($r, MYSQLI_ASSOC)) {

  #Now grab the statuses for each artist
  $status_query = "SELECT * FROM status_updates WHERE artist_id = '".$row['artist_id']."' ";
  $status_result = mysqli_query($dbc,$status_query)

}

但是我不確定如何遍歷並顯示返回的狀態更新？

這不是我的強項，因此任何指針都將不勝感激！

Answer 1

是什么使您無法執行與第一次查詢類似的操作？ 如下所示：

#Get the list of artists that the user has liked
$q = "SELECT * FROM artist_likes WHERE user_id = '1' ";
$r = mysqli_query($dbc,$q);
while ($row = mysqli_fetch_array($r, MYSQLI_ASSOC)) {

  #Now grab the statuses for each artist
  $status_query = "SELECT * FROM status_updates WHERE artist_id = '".$row['artist_id']."' ";
  $status_result = mysqli_query($dbc,$status_query)

  while($status_result_row = mysqli_fetch_assoc($status_result)) {
    echo $status_result_row['mycol']; // This is where you know better than us
  }
}

或者，如果這兩個表artist_likes和status_updates具有artist_id ，那么您可以僅使用一個查詢進行artist_id 。 （但不知道您是否要這樣做）。

Answer 2

只是為了避免多個查詢，您可以使用一個查詢，如下所示：

SELECT l.*, s.* 
from artist_likes l, status_updates s
WHERE
l.artist_id = s.artist_id and
l.user_id = '1'

要么

SELECT l.*, s.* 
from artist_likes l
JOIN status_updates s on (l.artist_id = s.artist_id)
WHERE
l.user_id = '1'