將應用程序名稱從存儲在NSDictionary中的JSON數據存儲在NSArray中

Question

我已經檢索了以下已成功存儲在NSDictionary中的JSON格式的響應表Server。

{
    "@companyName" = "MobileAPPSDeveloper";
    "@generatedDate" = "8/6/13 2:41 AM";
    "@version" = "1.0";
    application =     (

            {
        "@apiKey" = 234FXPQB36GHFF2334H;
        "@createdDate" = "2013-03-01";
        "@name" = FirstApp;
        "@platform" = iPhone;
    },
            {
        "@apiKey" = 3PF9WDY234546234M3Z;
        "@createdDate" = "2013-02-01";
        "@name" = SecondAPP;
        "@platform" = iPhone;
    },
            {
        "@apiKey" = NXGQXM2347Y23234Q4;
        "@createdDate" = "2013-05-22";
        "@name" = ThirdApp;
        "@platform" = Android;
    }
);

}

這是我使用的方法。

- (void)connectionDidFinishLoading:(NSURLConnection *)connection {

    NSString *responseString = [[NSString alloc] initWithData:responseData encoding:NSUTF8StringEncoding];
    [self convertDataIntoDictionary:responseData];
}

-(void)convertDataIntoDictionary:(NSData*)data{
    NSDictionary *dictionary;
    if (data.length>0) {
        NSError *parsingDataError;
        dictionary = [NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:&parsingDataError];

        if (parsingDataError) {
            //            [ErrorAlert showError:parsingDataError];
            NSString *recievedString = [[NSString  alloc] initWithData:data encoding:NSUTF8StringEncoding];
            NSLog(@"Data Conversion Error When Parsing: %@", recievedString);
        }
    }

    NSLog(@"Data back from server\n %@",dictionary);
    NSArray *applicationDetails = dictionary[@"application"];

}

我不能再走了嗎？

我想在數組中獲取APPS的全名。

任何幫助將不勝感激。

Answer 1

解析JSON的基礎是：

{}-dis代表字典
（）-dis代表數組

因此，在JSON ，根目錄有一個dictionary ， dictionary內部有一個密鑰application ，它包含一個Array 。

NSArray *applicationArray = [dictionary objectForKey:@"application"];
NSMutableArray *mutableAppNamesArray = [[NSMutableArray alloc]init];

在此數組內，每個索引都有三個NSDictionary ：

for(NSDictionary *dict in applicationArray){
  NSString *appName = [dict objectForKey:@"@name"];
  NSLog(@"app name : %@", appName);
  [mutableAppNamesArray addObject:appName];
}

NSArray * appNamesArray = [NSArray arrayWithArray:mutableAppNamesArray];

Answer 2

我認為這不是JSON的正確格式。 JSON對象通常包含“：”而不是“ =”

例子：-

{
products_id: "476",
products_model: "XOLO Play",
products_price: "15499.0000",
products_image: "xolo-play-play-t1000-.jpg",
products_date_available: null,
products_last_modified: "2013-08-04 06:04:11",
products_date_added: "2013-08-04 06:03:10",
manufacturers_id: "17",
products_status: "1",
products_rating: null,
category_id: "11"
},
{
products_id: "18",
products_model: "Nokia Lumia 820",
products_price: "8990.0000",
products_image: "samsung-galaxy-ace-duos-gsm-mobile-phone-large-1.jpg",
products_date_available: null,
products_last_modified: "2013-07-30 03:45:28",
products_date_added: "2013-01-23 00:52:00",
manufacturers_id: "2",
products_status: "1",
products_rating: "3",
category_id: "11"
}, 

但是，如果仍然需要解析它，則可以嘗試如下操作：

首先通過NSDictionary *array = [allValues objectForKey:@"application"];進入數組NSDictionary *array = [allValues objectForKey:@"application"]; 然后將每個索引指向NSDictionary，然后為密鑰對象。 如果它是您的服務器響應，則嘗試使其使用正確的JSON格式。