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[英]There are two columns in the new table(table1 join table2) which have the same column name, how to get the values of both respectively
[英]Get value in a table1 column with the column name is value in table2
我有兩個表,table2有nameColumn
,其中包含table1列的名稱
表格1
id|check|status|...|
1 |abc |1 |...|
表2
|nameColumn|...|
|check |...|
|status |...|
我希望在table1中獲取值,列名是table2中的值
$sql="SELECT * FROM `table1` WHERE `id` = 1 ";
$result = mysqli_query($conn,$sql) or die (mysql_error ());
$rowTable = mysqli_fetch_array($result);
$s = "SELECT * FROM table2";
$r = mysqli_query($conn,$s);
while($row1 = mysqli_fetch_array($r)){
$columnName = $row1['nameColumn'];
$value = $rowTable["'".$columnName."'"]; // fail why?
//$value = $rowTable['check']; // working?
}
我不知道為什么$value = $rowTable["'".$columnName."'"];
失敗的錯誤就像
Notice: Undefined index: 'check' ...
但如果我使用直接像$value = $rowTable['check']; // working why?
$value = $rowTable['check']; // working why?
如何解決這個問題
它失敗了,因為你添加了不必要的'
char。 嘗試下面的代碼
$value = $rowTable[$columnName];
$value = $rowTable['".$columnName."'];
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