[英]How to convert literal char hex value into the hex value itself?
我有一個應該存儲在unsigned char[64]
數組中的文字值。 如何將這些值轉換為十六進制等效值?
int main() {
unsigned char arry[1] = { 0xaa }
char* str = "fe"; //I want to store 0xfe on arry[0]
arry[0] = 0xfe; // this works, but I have to type it
arry[0] = 0x + str; //obviously fails
return 0;
}
有什么指針嗎?
arr[0] = strtol(str,NULL,16); // If one entry is big enough to hold it.
對於每個字符c
,值為:
if ('0' <= c && c <= '9') return c - '0';
if ('a' <= c && c <= 'f') return c - 'a' + 10;
if ('A' <= c && c <= 'F') return c - 'A' + 10;
// else error, invalid digit character
現在只需從左到右迭代字符串,將數字值相加,然后每次將結果乘以16。
(這是由基礎16的strto*l
函數中的標准庫實現的。)
使用函數strtol()
將字符串轉換為特定基數中的long: http : //www.cplusplus.com/reference/cstdlib/strtol/
“解析C-string str將其內容解釋為指定基數的整數,該數據作為long int值返回。如果endptr不是空指針,則該函數還將endptr的值設置為指向第一個字符在號碼之后。“
例:
#include <stdio.h> /* printf */
#include <stdlib.h> /* strtol */
int main ()
{
char szNumbers[] = "2001 60c0c0 -1101110100110100100000 0x6fffff";
char * pEnd;
long int li1, li2, li3, li4;
li1 = strtol (szNumbers,&pEnd,10);
li2 = strtol (pEnd,&pEnd,16);
li3 = strtol (pEnd,&pEnd,2);
li4 = strtol (pEnd,NULL,0);
printf ("The decimal equivalents are: %ld, %ld, %ld and %ld.\n", li1, li2, li3, li4);
return 0;
}
將任意長度的解決方案放在一起。
可悲的是,字符串到X是冗長的:討厭處理非十六進制字符串,奇數長度,太大等。
#include <string.h>
#include <stdio.h>
// S assumed to be long enough.
// X is little endian
void BigXToString(const unsigned char *X, size_t Length, char *S) {
size_t i;
for (i = Length; i-- > 0; ) {
sprintf(S, "%02X", X[i]);
S += 2;
}
}
int BigStringToX(const char *S, unsigned char X[], size_t Length) {
size_t i;
size_t ls = strlen(S);
if (ls > (Length * 2)) {
return 1; //fail, too big
}
int flag = ls & 1;
size_t Unused = Length - (ls/2) - flag;
memset(&X[Length - Unused], 0, Unused); // 0 fill unused
char little[3];
little[2] = '\0';
for (i = Length - Unused; i-- > 0;) {
little[0] = *S++;
little[1] = flag ? '\0' : *S++;
flag = 0;
char *endptr;
X[i] = (unsigned char) strtol(little, &endptr, 16);
if (*endptr) return 1; // non-hex found
if (*S == '\0') break;
}
return 0;
}
int main() {
unsigned char X[64];
char S[64 * 2 + 2];
char T[64 * 2 + 2];
strcpy(S, "12345");
BigStringToX(S, X, sizeof(X));
BigXToString(X, sizeof(X), T);
printf("'%s'\n", T);
return 0;
}
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