[英]Combining queries on the same table in to one query
我想從我的MySQL表中獲取一些統計信息,並希望將其保留在單個查詢中。 只是不知道如何(甚至可能)。 我有以下兩個查詢:
SELECT COUNT(*) AS `accept`
FROM `status`
WHERE `groupID` IN (98779,98780)
AND `group` = 'order'
AND `status` = 'accept'
和
SELECT COUNT(*) AS `price`
FROM `status`
WHERE `groupID` IN (98779, 98780)
AND `group` = 'quotation'
AND (`status` = 'final' OR `status` = 'manualprice')
我最好的建議是將它們合並到一個單獨的SELECT
如下所示:
SELECT
(SELECT COUNT(*) AS `accept`
FROM `status`
WHERE `groupID` IN (98779, 98780) AND `group` = 'order' AND `status` = 'accept') AS accept,
(SELECT COUNT(*) AS `price`
FROM `status`
WHERE `groupID` IN (98779, 98780) AND `group` = 'quotation' AND (`status` = 'final' OR `status` = 'manualprice')) AS price
有沒有更好的辦法?
這是另一種方式
SELECT SUM(`group` = 'order' AND `status` = 'accept') AS `ACCEPT`,
SUM(`group` = 'quotation' AND (`status` = 'final' OR `status` = 'manualprice')) AS `PRICE`
FROM `status`
WHERE `groupID` IN (98779, 98780) AND
`group` IN ('order', 'quotation') AND
`status` IN ('accept', 'final', 'manualprice')
SELECT
sum(if(`group` = 'order' AND `status` = 'accept', 1,0)) as `accept`,
sum(if(`group` = 'quotation' AND (`status` = 'final' OR `status` = 'manualprice'), 1,0)) as `price`
FROM
`status`
WHERE
`groupID` IN (98779,98780)
AND `group` IN ('order', 'quotation')
AND `status` IN ('accept', 'final', 'manualprice')
編輯這基本上與491243的其他答案相同。我使用了附加的if語句,似乎不一定需要。
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