Cypher - Where + Aggregate + With 問題

Question

我正在嘗試執行以下 Cypher 查詢

START b=node:customer_idx(ID = 'ABCD')   
MATCH p = b-[r1:LIKES]->stuff, someone_else_too-[r2:LIKES]->stuff
with b,someone_else_too, count(*) as matchingstuffcount
where matchingstuffcount > 1
//with   b, someone_else_too, matchingstuffcount, CASE WHEN ...that has r1, r2... END as SortIndex
return someone_else_too, SortIndex
order by SortIndex

上面的查詢工作正常，但是當我取消注釋較低的“with”時，我得到了以下錯誤

Unknown identifier `b`.
Unknown identifier `someone_else_too`.
Unknown identifier `matchingstuffcount`.
Unknown identifier `r1`.
Unknown identifier `r2`.

為了解決問題，我在頂部包含 r1 和 r2 - "with b,someone_else_too, count(*) as matchingstuffcount". 到"with b, r1, r2, someone_else_too, count(*) as matchingstuffcount". 這弄亂了我的count(*) > 1條件，因為 count(*) 沒有正確聚合。

在確保 Case When 也可以執行的同時過濾掉 count(*) > 1 的任何解決方法/建議？

Answer 1

在 neo4j 2.0 下通過console.neo4j.org我能夠得到以下查詢工作。 我試圖模仿你的結構，即WITH / WHERE / WITH / RETURN序列。 （如果我錯過了什么，請告訴我！）

START n=node:node_auto_index(name='Neo') 
MATCH n-[r:KNOWS|LOVES*]->m 
WITH n,COUNT(r) AS cnt,m 
WHERE cnt >1 
WITH n, cnt, m,  CASE WHEN m.name?='Cypher'  THEN 1  ELSE 0 END AS isCypher 
RETURN n AS Neo, cnt, m, isCypher 
ORDER BY cnt

在此處更新或更改。