[英]SQL Pivoting or Transposing or … column to row?
我有一個問題,在SQLfiddle中看起來更好: http ://www.sqlfiddle.com/#!3 / dffa1 /2
我為每個具有datestamp和測試結果的用戶提供了一個具有多行的表,我想將其轉置或旋轉為一行結果,如下所示,其中每個用戶都列出了所有時間和值結果:
USERID PSA1_time PSA1_result PSA2_time PSA2_result PSA3_time PSA3_result ...
1 1999-.... 2 1998... 4 1999... 6
3 1992... 4 1994 6
4 2006 ... 8
下表:
CREATE TABLE yourtable
([userid] int, [Ranking] int,[test] varchar(3), [Date] datetime, [result] int)
;
INSERT INTO yourtable
([userid], [Ranking],[test], [Date], [result])
VALUES
('1', '1', 'PSA', 1997-05-20, 2),
('1', '2','PSA', 1998-05-07, 4),
('1', '3','PSA', 1999-06-08, 6),
('1', '4','PSA', 2001-06-08, 8),
('1', '5','PSA', 2004-06-08, 0),
('3', '1','PSA', 1992-05-07, 4),
('3', '2','PSA', 1994-06-08, 6),
('4', '1','PSA', 2006-06-08, 8)
;
由於您希望將PIVOT列為兩列,因此我的建議是先取消date
和result
列的透視圖,然后再應用PIVOT函數。
取消透視過程將兩列date
和result
轉換為多行:
select userid,
col = test +'_'+cast(ranking as varchar(10))+'_'+ col,
value
from yourtable t1
cross apply
(
select 'time', convert(varchar(10), date, 120) union all
select 'result', cast(result as varchar(10))
) c (col, value)
參見演示 。 這將為您提供結果:
| USERID | COL | VALUE |
--------------------------------------
| 1 | PSA_1_time | 1997-05-20 |
| 1 | PSA_1_result | 2 |
| 1 | PSA_2_time | 1998-05-07 |
| 1 | PSA_2_result | 4 |
| 1 | PSA_3_time | 1999-06-08 |
現在您已經有了這種格式的數據,那么您就可以應用數據透視獲取col
每個項目的max
/ min
:
如果列數有限,則可以對查詢進行硬編碼:
select *
from
(
select userid,
col = test +'_'+cast(ranking as varchar(10))+'_'+ col,
value
from yourtable t1
cross apply
(
select 'time', convert(varchar(10), date, 120) union all
select 'result', cast(result as varchar(10))
) c (col, value)
) d
pivot
(
max(value)
for col in (PSA_1_time, PSA_1_result,
PSA_2_time, PSA_2_result,
PSA_3_time, PSA_3_result,
PSA_4_time, PSA_4_result,
PSA_5_time, PSA_5_result)
) piv;
如果您有未知的列,則需要使用動態SQL:
DECLARE @cols AS NVARCHAR(MAX),
@query AS NVARCHAR(MAX)
select @cols = STUFF((SELECT ',' + QUOTENAME(test +'_'+cast(ranking as varchar(10))+'_'+ col)
from yourtable
cross apply
(
select 'time', 1 union all
select 'result', 2
) c (col, so)
group by test, ranking, col, so
order by Ranking, so
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
set @query = 'SELECT userid,' + @cols + '
from
(
select userid,
col = test +''_''+cast(ranking as varchar(10))+''_''+ col,
value
from yourtable t1
cross apply
(
select ''time'', convert(varchar(10), date, 120) union all
select ''result'', cast(result as varchar(10))
) c (col, value)
) x
pivot
(
max(value)
for col in (' + @cols + ')
) p '
execute sp_executesql @query;
請參閱帶有演示的SQL Fiddle 。 這兩個版本都會給出結果:
| USERID | PSA_1_TIME | PSA_1_RESULT | PSA_2_TIME | PSA_2_RESULT | PSA_3_TIME | PSA_3_RESULT | PSA_4_TIME | PSA_4_RESULT | PSA_5_TIME | PSA_5_RESULT |
------------------------------------------------------------------------------------------------------------------------------------------------------
| 1 | 1997-05-20 | 2 | 1998-05-07 | 4 | 1999-06-08 | 6 | 2001-06-08 | 8 | 2004-06-08 | 0 |
| 3 | 1992-05-07 | 4 | 1994-06-08 | 6 | (null) | (null) | (null) | (null) | (null) | (null) |
| 4 | 2006-06-08 | 8 | (null) | (null) | (null) | (null) | (null) | (null) | (null) | (null) |
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